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anonymous
 one year ago
What is the change in entropy for a system that has 250 J of heat added to it at 25°C?
10 J/K, 0.84 J/K, 0.84 J/K, or 10 J/K
**thank you!!
anonymous
 one year ago
What is the change in entropy for a system that has 250 J of heat added to it at 25°C? 10 J/K, 0.84 J/K, 0.84 J/K, or 10 J/K **thank you!!

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1it is simple, we have to apply this formula: \[\Large \Delta S = \frac{Q}{T}\] where \delta S is the entropy change

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay!! so 250/25 = 10 ? so our solution is 10 J/K ?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1no, since T is the absolute temperature

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh i am unsure then :/

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have: \[T = t + 273\] t is the Celsius temperature

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh so we would get 273+25=298?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0250/298=0.84? so our solution is 0.84 J/K?
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