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I got 5040 at total number of ways they can stand together

Just like you did the last time.

Oh, and yes, you have three boys, so you also need to see that you can choose any 2 out of 3 boys.

See I messed up somewhere I got 5028...

720
4,320
3,600
4,000

Why 5C3?

\[7! - 2 \cdot \binom{3}{2}\cdot 6!\]

place girls in the blanks first
|dw:1432838542055:dw|

Oh, I see.

after that, we have 5 places for placing boys
|dw:1432838582145:dw|

but 1440 is not an option. so what is wrong?

Is 720 correct? Just wondering...

720 is an option

Is the option correct?

I dont think so?

What's the correct one?

Im not sure :/

i don't see how it cannot be 1440

1440 is that arrangement is the only the girls are sitting on the end seats

Pattern: gbgbgbg
# of arrangements: 4!*3! = 144

girls need not be in the ends
|dw:1432839047302:dw|

yeah :/ I am getting the same way... but this is not an answer...