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anonymous
 one year ago
In how many arrangements can 3 boys and 4 girls stand in a row such that no two boys are together?
anonymous
 one year ago
In how many arrangements can 3 boys and 4 girls stand in a row such that no two boys are together?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 @ParthKohli @AriPotta

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Number of ways that they can stand in  number of ways two boys can stand together. Note that the latter also covers the number of ways in which three boys can stand together.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Oh, and also keep in mind that they can permute among themselves, like @ganeshie8 spotted the last time.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got 5040 at total number of ways they can stand together

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How would you calculate the number of ways two boys can stand together? I feel like I am messing up there

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Just like you did the last time.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Oh, and yes, you have three boys, so you also need to see that you can choose any 2 out of 3 boys.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0See I messed up somewhere I got 5028...

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.24 girls can be arranged in 4! after that, 3 boys can be inserted in between the boys in 5C3 * 3! ways so in total we have 4! * 5C3*3! = 1440 ways

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0720 4,320 3,600 4,000

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1\[7!  2 \cdot \binom{3}{2}\cdot 6!\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2place girls in the blanks first dw:1432838542055:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2after that, we have 5 places for placing boys dw:1432838582145:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but 1440 is not an option. so what is wrong?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Is 720 correct? Just wondering...

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Is the option correct?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1What's the correct one?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2i don't see how it cannot be 1440

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01440 is that arrangement is the only the girls are sitting on the end seats

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Pattern: gbgbgbg # of arrangements: 4!*3! = 144

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2girls need not be in the ends dw:1432839047302:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0# of ways to fill the end seats: 4*3 = 12 # of ways to fill the other 5 seats: 5! # of arrangements: 12*5! = 1440

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah :/ I am getting the same way... but this is not an answer...

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2as the question stands, 1440 is the correct answer it just so happens that the options don't have the correct answer... inform ur teacher and move on to next q
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