Solve (z + 6)2 = 5. A. B. C. D.

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Solve (z + 6)2 = 5. A. B. C. D.

Mathematics
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Might help: http://www.mathpapa.com/algebra-calculator.html also shows you step by step
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i get confused after this?@KendrickLamar2014

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Other answers:

the answer choices didnt go through, i will wrte them out through the draw tool! @KendrickLamar2014
|dw:1432838835991:dw| @KendrickLamar2014
My guess would be choice C, not 100% sure tho.
im in between B and c?
OH MY GOODNESS, ok, I didn't realize that the 2 was an exponent!
that changes everything! (z + 6)^2 = 5
take the square root of each side subtract 6 from each side
\(\Large (z+6)^2=5\) \(\Large \sqrt{(z+6)^2}=\sqrt{5} \) \(\Large z+6=\pm \sqrt{5} \) \(\Large z+6-6=\pm\sqrt{5}-6\) \(\Large \color{green}{z=\pm\sqrt{5}-6}\)
Oh the 2 is an exponent. No wonder I could not find the answer :P
oh!
Good luck \(\Huge \color{red}{\star^{\star}}\)
So the answer is: ______
@Luigi0210 thats not an answer choice but whould it be c? its the closest one?
hint: A + B = B + A
is z a complex number?
when you add two terms together you can switch the order
okay so my best assumption would be b or c?
yes it is what it will equal up to!:) @Michele_Laino
It's magic! \(\Large \pm \sqrt{5}-6 = \color{red}{ -6\pm \sqrt{5}}=\color{green}{-6+\sqrt{5} ~or~ -6-\sqrt{5}}\)
if z is a complex number, then your equation, can be rewritten as below: \[\Large {\left( {x + 6 + iy} \right)^2} = 5\] wher i is such that: \[\Large {i^2} = - 1\] and I have used: \[\Large z = x + iy\]
so we are led to this subsequent algebraic system: \[\Large \left\{ {\begin{array}{*{20}{c}} {\left( {x + 6} \right)y = 0} \\ {{{\left( {x + 6} \right)}^2} - {y^2} = 5} \end{array}} \right.\] whose acceptable solutions are: \[\Large \left\{ \begin{gathered} {x_1} = - 6 + \sqrt 5 \hfill \\ {y_1} = 0 \hfill \\ \end{gathered} \right.,\quad \left\{ {\begin{array}{*{20}{c}} {{x_2} = - 6 - \sqrt 5 } \\ {{y_2} = 0} \end{array}} \right.\]

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