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anonymous
 one year ago
Solve (z + 6)2 = 5.
A.
B.
C.
D.
anonymous
 one year ago
Solve (z + 6)2 = 5. A. B. C. D.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Might help: http://www.mathpapa.com/algebracalculator.html also shows you step by step

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432838616284:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i get confused after this?@KendrickLamar2014

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the answer choices didnt go through, i will wrte them out through the draw tool! @KendrickLamar2014

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432838835991:dw @KendrickLamar2014

KendrickLamar2014
 one year ago
Best ResponseYou've already chosen the best response.1My guess would be choice C, not 100% sure tho.

KendrickLamar2014
 one year ago
Best ResponseYou've already chosen the best response.1@Michele_Laino

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im in between B and c?

KendrickLamar2014
 one year ago
Best ResponseYou've already chosen the best response.1@Luigi0210 @kropot72

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0help!!! @KendrickLamar2014 @ssssss @Vocaloid @AriPotta

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2OH MY GOODNESS, ok, I didn't realize that the 2 was an exponent!

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2that changes everything! (z + 6)^2 = 5

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2take the square root of each side subtract 6 from each side

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2\(\Large (z+6)^2=5\) \(\Large \sqrt{(z+6)^2}=\sqrt{5} \) \(\Large z+6=\pm \sqrt{5} \) \(\Large z+66=\pm\sqrt{5}6\) \(\Large \color{green}{z=\pm\sqrt{5}6}\)

KendrickLamar2014
 one year ago
Best ResponseYou've already chosen the best response.1Oh the 2 is an exponent. No wonder I could not find the answer :P

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2Good luck \(\Huge \color{red}{\star^{\star}}\)

KendrickLamar2014
 one year ago
Best ResponseYou've already chosen the best response.1So the answer is: ______

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Luigi0210 thats not an answer choice but whould it be c? its the closest one?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1is z a complex number?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2when you add two terms together you can switch the order

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so my best assumption would be b or c?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes it is what it will equal up to!:) @Michele_Laino

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2It's magic! \(\Large \pm \sqrt{5}6 = \color{red}{ 6\pm \sqrt{5}}=\color{green}{6+\sqrt{5} ~or~ 6\sqrt{5}}\)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1if z is a complex number, then your equation, can be rewritten as below: \[\Large {\left( {x + 6 + iy} \right)^2} = 5\] wher i is such that: \[\Large {i^2} =  1\] and I have used: \[\Large z = x + iy\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so we are led to this subsequent algebraic system: \[\Large \left\{ {\begin{array}{*{20}{c}} {\left( {x + 6} \right)y = 0} \\ {{{\left( {x + 6} \right)}^2}  {y^2} = 5} \end{array}} \right.\] whose acceptable solutions are: \[\Large \left\{ \begin{gathered} {x_1} =  6 + \sqrt 5 \hfill \\ {y_1} = 0 \hfill \\ \end{gathered} \right.,\quad \left\{ {\begin{array}{*{20}{c}} {{x_2} =  6  \sqrt 5 } \\ {{y_2} = 0} \end{array}} \right.\]
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