## anonymous one year ago If the entropy change for a system at 100.0°C is -20.0 J/K, then which of the following describes the heat? A. 7.46 kJ of heat added B. 2.00 kJ of heat removed C. 2.00 kJ of heat added D. 7.46 kJ of heat removed *thanks:)

1. Michele_Laino

hint: this formulas, in general, holds: $\Large \Delta S = \frac{Q}{T}$

2. Michele_Laino

formula*

3. anonymous

-20/100?

4. anonymous

:/

5. Michele_Laino

no, we have to write the inverse formula, then we have to compute the absolute temperature $\Large T = t + 273$ $\Large Q = T\Delta S$

6. anonymous

ohh okay! so 373 * -20 ? and we get-7460? so that means choice D? 7.46 kJ heat removed? since it is negative?

7. Michele_Laino

that's right!

8. Michele_Laino

congratulations!!!!!

9. anonymous

yayy!! thank you:)

10. Michele_Laino

thank you!! :D