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anonymous

  • one year ago

If the entropy change for a system at 100.0°C is -20.0 J/K, then which of the following describes the heat? A. 7.46 kJ of heat added B. 2.00 kJ of heat removed C. 2.00 kJ of heat added D. 7.46 kJ of heat removed *thanks:)

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  1. Michele_Laino
    • one year ago
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    hint: this formulas, in general, holds: \[\Large \Delta S = \frac{Q}{T}\]

  2. Michele_Laino
    • one year ago
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    formula*

  3. anonymous
    • one year ago
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    -20/100?

  4. anonymous
    • one year ago
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    :/

  5. Michele_Laino
    • one year ago
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    no, we have to write the inverse formula, then we have to compute the absolute temperature \[\Large T = t + 273\] \[\Large Q = T\Delta S\]

  6. anonymous
    • one year ago
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    ohh okay! so 373 * -20 ? and we get-7460? so that means choice D? 7.46 kJ heat removed? since it is negative?

  7. Michele_Laino
    • one year ago
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    that's right!

  8. Michele_Laino
    • one year ago
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    congratulations!!!!!

  9. anonymous
    • one year ago
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    yayy!! thank you:)

  10. Michele_Laino
    • one year ago
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    thank you!! :D

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