is3535
  • is3535
A jewelry stand sells 5 different pairs of earrings. The earrings sell for $12, $9, $6, $8, and $10. What is the mean absolute deviation of the prices? Round to the nearest cent, if necessary.
Mathematics
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
is3535
  • is3535
@SickTwistd
anonymous
  • anonymous
i know MAD
anonymous
  • anonymous
Give me a sec plz

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More answers

is3535
  • is3535
12+9+6+8+10=45 divided by 5=9 the mean absolute deviation is 9
anonymous
  • anonymous
No its 2.4
is3535
  • is3535
so 2.4
anonymous
  • anonymous
All the #'s added up, then / that # by how many #'s there are, then subtract that from all of the #'s, then take the distance from all of those numbers to zero and divide it by... one sec sorry
anonymous
  • anonymous
its a bit complicated
is3535
  • is3535
@Vocaloid
is3535
  • is3535
so 2.4
anonymous
  • anonymous
http://www.alcula.com/php_dir/latexrender/pictures/ce9496dc8cf7a1f4712320605a3c7ee6.png
is3535
  • is3535
or 9
anonymous
  • anonymous
2.4
is3535
  • is3535
ok
is3535
  • is3535
A quality-control center finds that 2 out of 250 toy trains are defective. How many trains would they expect to be defective in a batch of 10,000? A. 250 B. 125 C. 80 D. 40
anonymous
  • anonymous
r u in k12?
anonymous
  • anonymous
sorry im late
anonymous
  • anonymous
@is3535 ?
anonymous
  • anonymous
i just joined yesterday, so this is all new to me XD
anonymous
  • anonymous
:D
is3535
  • is3535
yes
anonymous
  • anonymous
im i k12 yea
anonymous
  • anonymous
me 2. what grade?
anonymous
  • anonymous
7th
is3535
  • is3535
|dw:1432841369245:dw|
is3535
  • is3535
80
is3535
  • is3535
A quality-control center finds that 2 out of 250 toy trains are defective. How many trains would they expect to be defective in a batch of 10,000? A. 250 B. 125 C. 80 D. 40
anonymous
  • anonymous
im in 7th. lol im REALLy good @ math. if i were in a room of 100 people, i would be better than 96 of them. based on my scantron
anonymous
  • anonymous
80
anonymous
  • anonymous
anyways, ive gtg do MY K12 work. ttyl! have a gr8 day!
anonymous
  • anonymous
and i agree 80.
anonymous
  • anonymous
thanks anyone have twitter?
anonymous
  • anonymous
this cal. will help btw :) http://www.alcula.com/calculators/statistics/mean-absolute-deviation/
anonymous
  • anonymous
i do. its TheOrion101
anonymous
  • anonymous
if u do, follow me @johnnycahun
anonymous
  • anonymous
kk i will if i can. Bye!
anonymous
  • anonymous
I'll follow u orion
anonymous
  • anonymous
;) bye

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