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anonymous
 one year ago
What is the energy of a photon of light having a wavelength of 4.5 x 107 meters? (Planck’s constant is 6.626 x 1034 joule seconds; the speed of light is 2.998 x 108 m/s)
2.9817 x 1040 joules
4.4143 x 1019 joules
6.6745 x 1026 joules second
9.9456 x 1049 joules
19.864 x 1026 joules/second
anonymous
 one year ago
What is the energy of a photon of light having a wavelength of 4.5 x 107 meters? (Planck’s constant is 6.626 x 1034 joule seconds; the speed of light is 2.998 x 108 m/s) 2.9817 x 1040 joules 4.4143 x 1019 joules 6.6745 x 1026 joules second 9.9456 x 1049 joules 19.864 x 1026 joules/second

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Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.0E = energy of photon = hc/lambda, where h is plank's constant, c is the speed of light, and lambda is the wavelength make sure all units are consistent

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2energy E carried by a photon is given by the subsequent formula: \[\Large E = h\nu \] where \nu is the frequency of our photon, namely \[\Large \nu = \frac{c}{\lambda }\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2c is the light speed

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2\lambda is the wavelength

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.0@briannaboswell: energy of photon = E c = speed of light = 2.998*10^8 lambda = wavelength = 4.5 x 107 m h = plank's constant = 6.626 x 1034 E = h*c/(lambda) all you have to do is plug in the values of h, c, and lambda...

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2so, substituting, we can write: \[\Large E = \frac{{hc}}{\lambda } = \frac{{6.62 \times {{10}^{  34}} \times 3 \times {{10}^8}}}{{4.5 \times {{10}^{  7}}}} = ...Joules\]
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