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anonymous
 one year ago
In triangle ABC , m angle A=41 degrees, m angle B=32 degrees and AC= 9 inches what is AB to the nearest tenth of an inch
a. 13.1 in
b. 13.6 in
c. 16.2 in
d. 16.9 in
anonymous
 one year ago
In triangle ABC , m angle A=41 degrees, m angle B=32 degrees and AC= 9 inches what is AB to the nearest tenth of an inch a. 13.1 in b. 13.6 in c. 16.2 in d. 16.9 in

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432846650149:dw I'm assuming it looks like this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i guess? it didnt have a picture on this one

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1So this can just be solved with the law of sines You have your triangle *drawn above* and you have the length of 1 other side So we can use \[\large \frac{sin(32)}{9} = \frac{sin(107)}{AB}\] And solve for AB

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok and i solve for AB how? @johnweldon1993

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Wait, first, have you seen this before? The law of sines?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you walk me through this? or would that be asking for to much? @johnweldon1993 and no i changed schools and skiped like 3 units so im trying to get all of this

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1No never asking too much :) but first, what class is the for? I just dont want to introduce something you wouldnt even be learning :)

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Okay then yeah this applies :) Okay so...in general You have a triangle dw:1432852105182:dw

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1So first we need to solve for angle C We know that the interior angles of a triangle always add to 180 So since we have 41...and 32...we have 73 of those 180 degrees So angle C must be the remaining 107 degrees right?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1does that make sense? Gotta make sure you're staying with me :)

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1So now, we apply the law of sines What THAT states...is: \[\large \frac{sin(A)}{a} = \frac{sin(B)}{b} = \frac{sin(C)}{c}\] Where A,B and C are the angle measurements we have and a,b and c are the side lengths we have

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Now the way we use it....is if we have angle A, then side "A" would be the side the angle faces dw:1432852557818:dw

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1So...since you have side B right...here it would be AC dw:1432852698148:dw And you want to solve for side C which here would be AB dw:1432852734405:dw we can write \[\large \frac{sin(\text{Angle of B)}}{\text{Length of side B = 9}} = \frac{sin(\text{angle of C)}}{\text{length of side C = ???}}\] \[\large \frac{sin(32)}{9} = \frac{sin(107)}{AB}\]

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1And then we just solve for AB Now to do that...we just cross multiply \[\large ABsin(32) = 9sin(107)\] And divide both sides by the sin(32) so \[\large AB = \frac{9sin(107)}{sin(32)}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok.. um sorry its taking a while for me to catch on

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1No that's fine :) just tell me if you want me to explain a part over :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it was pretty explanatory just takes a lot of practice thank you so much!
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