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anonymous

  • one year ago

WILL FAN!!!!!!!!!!!!!!! A zoo train ride costs $4 per adult and $1 per child. On a certain day, the total number of adults (a) and children (c) who took the ride was 27, and the total money collected was $60. What was the number of children and the number of adults who took the train ride that day, and which pair of equations can be solved to find the numbers?

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  1. anonymous
    • one year ago
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    A 11 children and 16 adults Equation 1: a + c = 27 Equation 2: 4a + c = 60 B 16 children and 11 adults Equation 1: a + c = 27 Equation 2: 4a + c = 60 C11 children and 16 adults Equation 1: a + c = 27 Equation 2: 4a − c = 60 D16 children and 11 adults Equation 1: a + c = 27 Equation 2: 4a − c = 60

  2. Vocaloid
    • one year ago
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    let a = the number of adults let c = the number of children we know that the total number of children and adults is 27, so a + c = 27 the total amount of money collected is the adult ticket price*a + the child ticket price*c = 60 the adult ticket price is $4 the child's ticket price is $1 a + c = 27 4a + c = 60 solve for a and c

  3. hockeychick23
    • one year ago
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    B) 16 children and 11 adults Equation 1: a + c = 27 Equation 2: 4a + c = 60 If we plug the numbers into each equation we get: 11+16=27 4(11)+16--> 44+16= 60

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