anonymous
  • anonymous
PLEASE HELP WILL GIVE MEDAL, FAN, AND TESTIMONIAL!
Mathematics
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anonymous
  • anonymous
PLEASE HELP WILL GIVE MEDAL, FAN, AND TESTIMONIAL!
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
|dw:1432858373212:dw|

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anonymous
  • anonymous
It's on quadrant I
anonymous
  • anonymous
Now we have to find the translated point.
anonymous
  • anonymous
(x + 1, y - 5) replace x and y with the original points (4, 2)
anonymous
  • anonymous
ok
anonymous
  • anonymous
What do you think it is :)
anonymous
  • anonymous
(5,-3)
anonymous
  • anonymous
Yep!
anonymous
  • anonymous
Now we have to find what quadrant it's in.
anonymous
  • anonymous
|dw:1432858782385:dw|
anonymous
  • anonymous
It's in quadrant IV
anonymous
  • anonymous
Now we have to reflect it across the y axis|dw:1432858919538:dw|
anonymous
  • anonymous
Your guess?
anonymous
  • anonymous
(-3, 5)?
anonymous
  • anonymous
Nope, y stays the same.
anonymous
  • anonymous
It will be (-5, -3)
anonymous
  • anonymous
What quadrant do you think it's in?
anonymous
  • anonymous
III
anonymous
  • anonymous
Yep :)
anonymous
  • anonymous
And we're done.
anonymous
  • anonymous
Do you need more help ?
anonymous
  • anonymous
Thanks! well if you could help me with 2 more they're not as hard as this one, there much more easier.
anonymous
  • anonymous
Sure :)
anonymous
  • anonymous
Also remember that when you reflect a point across the y axis, the y will always remain the same. Only the x will change.

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