anonymous one year ago Find the derivative of f(x)=sqrt(x+2), and state the domain of f(x) and f'(x). What are the domains?

1. anonymous

The domain is all x values greater than -2. This is because one cannot square root a negative value

2. anonymous

Is that for both f(x) and f'(x)?

3. anonymous

*greater than or equal. you can take the square root of zero. No, hold on I'll write it out quick

4. anonymous

$f(x)=\sqrt{x+2}$ HAS DOMAIN $$x+2\geq 0$$ or $$x\geq -2$$

5. anonymous

f' the domain is x is greater than -2. This time it cannot equal -2

6. anonymous

$f'(x)=\frac{1}{2\sqrt{x+2}}$ has domain $$x>0$$ almost the same !

7. anonymous

no x can equal -1 in f'

8. anonymous

no i made a mistake, meant $$x>-2$$ so almost the same only difference is at $$x=-2$$ where $$f$$ is defined and $$f'$$ is not

9. anonymous

yep

10. anonymous

domain of $$f'$$: $$x>-2$$