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anonymous

  • one year ago

Find the derivative of f(x)=sqrt(x+2), and state the domain of f(x) and f'(x). What are the domains?

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  1. anonymous
    • one year ago
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    The domain is all x values greater than -2. This is because one cannot square root a negative value

  2. anonymous
    • one year ago
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    Is that for both f(x) and f'(x)?

  3. anonymous
    • one year ago
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    *greater than or equal. you can take the square root of zero. No, hold on I'll write it out quick

  4. anonymous
    • one year ago
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    \[f(x)=\sqrt{x+2}\] HAS DOMAIN \(x+2\geq 0\) or \(x\geq -2\)

  5. anonymous
    • one year ago
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    f' the domain is x is greater than -2. This time it cannot equal -2

  6. anonymous
    • one year ago
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    \[f'(x)=\frac{1}{2\sqrt{x+2}}\] has domain \(x>0\) almost the same !

  7. anonymous
    • one year ago
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    no x can equal -1 in f'

  8. anonymous
    • one year ago
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    no i made a mistake, meant \(x>-2\) so almost the same only difference is at \(x=-2\) where \(f\) is defined and \(f'\) is not

  9. anonymous
    • one year ago
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    yep

  10. anonymous
    • one year ago
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    domain of \(f'\): \(x>-2\)

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