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anonymous
 one year ago
Find the derivative of f(x)=sqrt(x+2), and state the domain of f(x) and f'(x). What are the domains?
anonymous
 one year ago
Find the derivative of f(x)=sqrt(x+2), and state the domain of f(x) and f'(x). What are the domains?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The domain is all x values greater than 2. This is because one cannot square root a negative value

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is that for both f(x) and f'(x)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0*greater than or equal. you can take the square root of zero. No, hold on I'll write it out quick

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[f(x)=\sqrt{x+2}\] HAS DOMAIN \(x+2\geq 0\) or \(x\geq 2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f' the domain is x is greater than 2. This time it cannot equal 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[f'(x)=\frac{1}{2\sqrt{x+2}}\] has domain \(x>0\) almost the same !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no x can equal 1 in f'

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no i made a mistake, meant \(x>2\) so almost the same only difference is at \(x=2\) where \(f\) is defined and \(f'\) is not

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0domain of \(f'\): \(x>2\)
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