anonymous
  • anonymous
Beth has built a simple series circuit using wire, a battery, a lightbulb, and a switch. The bulb, however, does not light up when the switch is closed. Which describes a step that will help troubleshoot and work toward the solution of this problem? A. Change the wiring scheme to parallel. B. Use an electrical meter to test the voltage of the battery. C. Reverse the way the wire is connected to the poles of the battery. D. Shorten the length of wire between the battery and the switch
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@iGreen
anonymous
  • anonymous
@JoKeR0331
anonymous
  • anonymous
@Kitten_is_back

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shamim
  • shamim
2 parallel resistance have same potential dial difference
shamim
  • shamim
And each of those 2 resistor has same potential difference as the battery
shamim
  • shamim
So each resistance connected in parallel will get enough potential difference
shamim
  • shamim
But if we connect 2 or more resistance in series, then the sum of potential difference of each resistance is equal the potential difference of battery
shamim
  • shamim
So potential difference across any resistor connected in series is much less than the potential difference of battery
shamim
  • shamim
U know longer wire has more resistance than the resistance of shorter wire
amistre64
  • amistre64
what steps would YOU take? Which one of them is listed?
shamim
  • shamim
D? @amistre64
amistre64
  • amistre64
its either the bulb, the switch, a connection in the wire, or a battery issue.
shamim
  • shamim
I think the whole connecting wire should b shorter
shamim
  • shamim
So the resistance of wire will b less
shamim
  • shamim
So the potential difference across the whole wire will b low
shamim
  • shamim
And the potential difference across the bulb will b higher to light up

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