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  1. mathmate
    • one year ago
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    Are you familiar with like terms and unlike terms?

  2. anonymous
    • one year ago
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    no not really

  3. mathmate
    • one year ago
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    Like terms are those terms that have the same powers of variables, even though the coefficient (including the sign) may be different. For example, 2x^2 and -6.5x^2 are like terms.

  4. mathmate
    • one year ago
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    When you have to add or subtract two expressions, you need to group together the like terms, because you can then add/subtract the coefficients among the like terms.

  5. mathmate
    • one year ago
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    Are you following so far?

  6. anonymous
    • one year ago
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    yes , i'm starting to get it

  7. mathmate
    • one year ago
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    So what would be 4x^3 -2x^3?

  8. anonymous
    • one year ago
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    would it be 2x^3

  9. mathmate
    • one year ago
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    Correct. Just think of x^3 as apples, x^2 as oranges, so what would be 5x^3-3x^2+4x^3-x^2 ?

  10. anonymous
    • one year ago
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    i think it would be x^2(9x−4) but i'm not sure

  11. mathmate
    • one year ago
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    Yes, this is correct. 9x^3-4x^2 would have been totally acceptable as well. Good!

  12. mathmate
    • one year ago
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    Are you familiar with the distributive property of multiplication?

  13. mathmate
    • one year ago
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    Like 2(x+2) = 2x+4

  14. anonymous
    • one year ago
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    yes i'm familiar with it

  15. mathmate
    • one year ago
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    ok, now we can get to work on the problem. Can you simplify the expression by removing all parentheses? (-3y^2-8)-(-5y^2+1)

  16. anonymous
    • one year ago
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    yeah i got this part, its 2y^2-9 , but i can't the other part of it which is y^2-?

  17. mathmate
    • one year ago
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    2y^2-9 is the complete answer. Put a 2 in the box before the y^2, and put a 9 in the other box. I think the program is kind of babysitting us.

  18. anonymous
    • one year ago
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    so the answer would look like this right, we get 2y^2-9

  19. mathmate
    • one year ago
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    Exactly the same as yours.

  20. anonymous
    • one year ago
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    woww thank you some much , for explaining it to me very well

  21. mathmate
    • one year ago
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    You're welcome! :)

  22. anonymous
    • one year ago
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    k..

  23. anonymous
    • one year ago
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    Help again please

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  24. anonymous
    • one year ago
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    @mathmate

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