## anonymous one year ago Please help me with this algebra 1 problem! I will give a medal and follow. Solve: 8/x+15/x^2=-1 a. x=5,-3 b. x=-5,-3 c. x= -5, 3 d. x= 5,3 I know how to do this problem when numbers are the denominators with the xs. It's just the xs with no numbers and the one that is cubed really confuses me.

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1. anonymous

@rishavraj

2. anonymous

*I meant squared

3. rishavraj

$\frac{ 8 }{ x } + \frac{ 15 }{ x^2 } = -1$ so get the LCM of denominators i.e x^2 so it would be $\frac{ 8x + 15 }{ x^2 } = -1$

4. anonymous

so then do i cross multiply?

5. anonymous

what happened to the other x?

6. rishavraj

yeah now u need to cross multiply...... for the another x.....hmmmmmm u tell me how u slove 8/3 + 7/9