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anonymous
 one year ago
Please help me with this algebra 1 problem! I will give a medal and follow.
Solve: 8/x+15/x^2=1
a. x=5,3
b. x=5,3
c. x= 5, 3
d. x= 5,3
I know how to do this problem when numbers are the denominators with the xs. It's just the xs with no numbers and the one that is cubed really confuses me.
anonymous
 one year ago
Please help me with this algebra 1 problem! I will give a medal and follow. Solve: 8/x+15/x^2=1 a. x=5,3 b. x=5,3 c. x= 5, 3 d. x= 5,3 I know how to do this problem when numbers are the denominators with the xs. It's just the xs with no numbers and the one that is cubed really confuses me.

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rishavraj
 one year ago
Best ResponseYou've already chosen the best response.4\[\frac{ 8 }{ x } + \frac{ 15 }{ x^2 } = 1\] so get the LCM of denominators i.e x^2 so it would be \[\frac{ 8x + 15 }{ x^2 } = 1 \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so then do i cross multiply?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what happened to the other x?

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.4yeah now u need to cross multiply...... for the another x.....hmmmmmm u tell me how u slove 8/3 + 7/9
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