Please help me with this algebra 1 problem! I will give a medal and follow. Solve: 8/x+15/x^2=-1 a. x=5,-3 b. x=-5,-3 c. x= -5, 3 d. x= 5,3 I know how to do this problem when numbers are the denominators with the xs. It's just the xs with no numbers and the one that is cubed really confuses me.

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Please help me with this algebra 1 problem! I will give a medal and follow. Solve: 8/x+15/x^2=-1 a. x=5,-3 b. x=-5,-3 c. x= -5, 3 d. x= 5,3 I know how to do this problem when numbers are the denominators with the xs. It's just the xs with no numbers and the one that is cubed really confuses me.

Mathematics
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*I meant squared
\[\frac{ 8 }{ x } + \frac{ 15 }{ x^2 } = -1\] so get the LCM of denominators i.e x^2 so it would be \[\frac{ 8x + 15 }{ x^2 } = -1 \]

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Other answers:

so then do i cross multiply?
what happened to the other x?
yeah now u need to cross multiply...... for the another x.....hmmmmmm u tell me how u slove 8/3 + 7/9

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