anonymous
  • anonymous
Please help me with this algebra 1 problem! I will give a medal and follow. Solve: 8/x+15/x^2=-1 a. x=5,-3 b. x=-5,-3 c. x= -5, 3 d. x= 5,3 I know how to do this problem when numbers are the denominators with the xs. It's just the xs with no numbers and the one that is cubed really confuses me.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@rishavraj
anonymous
  • anonymous
*I meant squared
rishavraj
  • rishavraj
\[\frac{ 8 }{ x } + \frac{ 15 }{ x^2 } = -1\] so get the LCM of denominators i.e x^2 so it would be \[\frac{ 8x + 15 }{ x^2 } = -1 \]

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anonymous
  • anonymous
so then do i cross multiply?
anonymous
  • anonymous
what happened to the other x?
rishavraj
  • rishavraj
yeah now u need to cross multiply...... for the another x.....hmmmmmm u tell me how u slove 8/3 + 7/9

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