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anonymous

  • one year ago

will give medal and fan!

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  1. anonymous
    • one year ago
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    The function H(t) = -16t2 + vt + s shows the height H (t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second. Part A: The projectile was launched from a height of 100 feet with an initial velocity of 60 feet per second. Create an equation to find the time taken by the projectile to fall on the ground. (2 points) Part B: What is the maximum height that the projectile will reach? Show your work. (2 points) Part C: Another object moves in the air along the path of g(t) = 20 + 38.7t where g(t) is the height, in feet, of the object from the ground at time t seconds. Use a table to find the approximate solution to the equation H(t) = g(t), and explain what the solution represents in the context of the problem? [Use the function H(t) obtained in Part A, and estimate using integer values] (4 points) Part D: Do H(t) and g(t) intersect when the projectile is going up or down, and how do you know? (2 points)

  2. JoannaBlackwelder
    • one year ago
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    We are given the function with constants for the height and speed. Can you plug them in?

  3. anonymous
    • one year ago
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    H(t)=-16t^2+100(60)+s would that right @JoannaBlackwelder

  4. anonymous
    • one year ago
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    @triciaal

  5. anonymous
    • one year ago
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    @Vocaloid

  6. JoannaBlackwelder
    • one year ago
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    Close, I get: 16t^2 + 60t +100

  7. JoannaBlackwelder
    • one year ago
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    v=60 s=100

  8. anonymous
    • one year ago
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    can you help me with parts c and d @JoannaBlackwelder

  9. JoannaBlackwelder
    • one year ago
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    Sure, can you make a table of values of H(t) and g(t)?

  10. anonymous
    • one year ago
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    g(t) h(t) 1 58.7 144 2 97.4 156 3 136.1 136 4 174.8 84

  11. anonymous
    • one year ago
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    is that ok @JoannaBlackwelder

  12. JoannaBlackwelder
    • one year ago
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    Yep, that's a good start? Do you know what we are looking for in the table?

  13. anonymous
    • one year ago
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    the point were h(t)=g(t)

  14. JoannaBlackwelder
    • one year ago
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    Yep, the point or points. :-) Do you see one so far?

  15. anonymous
    • one year ago
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    at 3 they are the closest

  16. JoannaBlackwelder
    • one year ago
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    Yep, I think we can say they are about the same at t=3. :-) So, what does that represent in the problem?

  17. anonymous
    • one year ago
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    the point were they intersect?

  18. JoannaBlackwelder
    • one year ago
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    Yep, that would be the point where the two objects would hit each other. :-)

  19. anonymous
    • one year ago
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    for part d how do I know whether or not it is going down or up?

  20. JoannaBlackwelder
    • one year ago
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    It would be going up if it is before the vertex, down if it is after.

  21. JoannaBlackwelder
    • one year ago
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    Since the parabola is upside down

  22. anonymous
    • one year ago
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    it would be going down ,right?

  23. JoannaBlackwelder
    • one year ago
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    Yep :-)

  24. anonymous
    • one year ago
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    can you help me with a couple more equations.

  25. JoannaBlackwelder
    • one year ago
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    Possibly. But open a new question, please. And tag me :-)

  26. anonymous
    • one year ago
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    ok

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