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anonymous
 one year ago
will give medal and fan!
anonymous
 one year ago
will give medal and fan!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The function H(t) = 16t2 + vt + s shows the height H (t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second. Part A: The projectile was launched from a height of 100 feet with an initial velocity of 60 feet per second. Create an equation to find the time taken by the projectile to fall on the ground. (2 points) Part B: What is the maximum height that the projectile will reach? Show your work. (2 points) Part C: Another object moves in the air along the path of g(t) = 20 + 38.7t where g(t) is the height, in feet, of the object from the ground at time t seconds. Use a table to find the approximate solution to the equation H(t) = g(t), and explain what the solution represents in the context of the problem? [Use the function H(t) obtained in Part A, and estimate using integer values] (4 points) Part D: Do H(t) and g(t) intersect when the projectile is going up or down, and how do you know? (2 points)

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1We are given the function with constants for the height and speed. Can you plug them in?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0H(t)=16t^2+100(60)+s would that right @JoannaBlackwelder

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Close, I get: 16t^2 + 60t +100

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you help me with parts c and d @JoannaBlackwelder

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Sure, can you make a table of values of H(t) and g(t)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0g(t) h(t) 1 58.7 144 2 97.4 156 3 136.1 136 4 174.8 84

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is that ok @JoannaBlackwelder

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Yep, that's a good start? Do you know what we are looking for in the table?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the point were h(t)=g(t)

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Yep, the point or points. :) Do you see one so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0at 3 they are the closest

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Yep, I think we can say they are about the same at t=3. :) So, what does that represent in the problem?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the point were they intersect?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Yep, that would be the point where the two objects would hit each other. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for part d how do I know whether or not it is going down or up?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1It would be going up if it is before the vertex, down if it is after.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Since the parabola is upside down

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it would be going down ,right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you help me with a couple more equations.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Possibly. But open a new question, please. And tag me :)
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