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I got 2(cos 90° + i sin 90°) but that was wrong and I don't understand why.
ok cos(90 deg)=0 and sin(90 deg)=1 so you have 2(0+i*1) 2(i*1) 2(i) 2i
but you wanted -2i
why don't you just change 2 to -2
or you could go with changing the angle from 90 deg to 270 deg since sin will be negative 1there
let me know if you need more assistance @hermom1967
So it would be 2(cos 270° + i sin 270°)?
Is that because it's in a different quadrant?
right since cos(270 deg)=0 and sin(270 deg)=-1 so you would have 2(0+i[-1]) =2[i[-1]] =2[-i] =-2i
also have you ever graphed things in the form a+bi?
we have a is 0 which means we don't go left or right any but b is -2 which means we have to go down 2 units
Okay, I understand that
you can think of a+bi as if you are plotting points (a,b)
you know when graphing
and yeah you could have chose the angle to be 90 deg if you made r negative like you could have done -2(cos(90)+isin(90))
Okay, thank you so much! Now to be able to retain that... LOL
I think it will get a little easier when you guys go over plotting things in form a+bi or plotting also polar coordinates, you know where you plot things in the form (r,theta)