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I got 2(cos 90° + i sin 90°)
but that was wrong and I don't understand why.

ok cos(90 deg)=0
and sin(90 deg)=1
so you have
2(0+i*1)
2(i*1)
2(i)
2i

but you wanted -2i

why don't you just change 2 to -2

or you could go with changing the angle from 90 deg to 270 deg
since sin will be negative 1there

let me know if you need more assistance @hermom1967

So it would be 2(cos 270° + i sin 270°)?

Is that because it's in a different quadrant?

right since cos(270 deg)=0 and sin(270 deg)=-1
so you would have 2(0+i[-1])
=2[i[-1]]
=2[-i]
=-2i

also have you ever graphed things in the form a+bi?

No

|dw:1432867663223:dw|

Okay, I understand that

you can think of a+bi
as if you are plotting points (a,b)

you know when graphing

|dw:1432867746418:dw|

Okay, thank you so much! Now to be able to retain that... LOL