I am really having trouble with how to set up the equation to solve this,
Calculate the number of moles of NaHCO3 required to neutralize the CH3COOH in the vinegar.
it took 9.5mL of NaHCO3, and 9.86mL of CH3COOH

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The density of acetic acid is 1.01 g/mL

Do you have the molarity of the sodium bicarbonate mixture?

the molarity is 1.14M

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