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Curry
 one year ago
Question regarding finding the equivalence class.
Curry
 one year ago
Question regarding finding the equivalence class.

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Curry
 one year ago
Best ResponseYou've already chosen the best response.0I am having trouble finding the correspoinding equivalence class. :/ How do i find it for this problem?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you showed it was an equivalence relation right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what, for example, is in the equivalence class of \(2\)?

Curry
 one year ago
Best ResponseYou've already chosen the best response.0and when I'm proving that it's a equivalence relation, here was my work. can i have some validation here?

Curry
 one year ago
Best ResponseYou've already chosen the best response.0So wouldn't the equivalence class for 2 be 2 and +2?

Curry
 one year ago
Best ResponseYou've already chosen the best response.0so for any integer n, it'd be, n and +n?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in fact all equivalence classes have to elements, except 0 which is in its own class

Curry
 one year ago
Best ResponseYou've already chosen the best response.0what would be the correct notation to write that all?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk depends on how you write them

Curry
 one year ago
Best ResponseYou've already chosen the best response.0well usually, in class they said, {elements} << that was generally how they expressed it. but for htis case, i'm not too sure how to write it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i do no like your proof however, you have the if and then in the wrong place

Curry
 one year ago
Best ResponseYou've already chosen the best response.0oo! kk, i'll go back and edit that. How should i make it better?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you want to show it is reflexive meaning \(aRa\) you do not assume \(aRa\) you prove \(aRa\) i.e by saying "because a=a, it is true that \(aRa\) so R is reflexive
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