Curry
  • Curry
Question regarding finding the equivalence class.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Curry
  • Curry
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Curry
  • Curry
I am having trouble finding the correspoinding equivalence class. :/ How do i find it for this problem?
Curry
  • Curry
@dan815 @ganeshie8

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anonymous
  • anonymous
you showed it was an equivalence relation right?
anonymous
  • anonymous
so what, for example, is in the equivalence class of \(2\)?
Curry
  • Curry
and when I'm proving that it's a equivalence relation, here was my work. can i have some validation here?
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Curry
  • Curry
So wouldn't the equivalence class for 2 be -2 and +2?
anonymous
  • anonymous
yes
Curry
  • Curry
so for any integer n, it'd be, -n and +n?
anonymous
  • anonymous
in fact all equivalence classes have to elements, except 0 which is in its own class
Curry
  • Curry
what would be the correct notation to write that all?
anonymous
  • anonymous
idk depends on how you write them
anonymous
  • anonymous
\[\{a,-a\}\] maybe
Curry
  • Curry
well usually, in class they said, {elements} << that was generally how they expressed it. but for htis case, i'm not too sure how to write it.
Curry
  • Curry
and a = N?
anonymous
  • anonymous
i do no like your proof however, you have the if and then in the wrong place
Curry
  • Curry
oo! kk, i'll go back and edit that. How should i make it better?
anonymous
  • anonymous
you want to show it is reflexive meaning \(aRa\) you do not assume \(aRa\) you prove \(aRa\) i.e by saying "because |a|=|a|, it is true that \(aRa\) so R is reflexive

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