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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Simplify :/ . \[\frac{ 3m-1 }{ m-2 }-\frac{ 2m+1 }{ m-2 }\]
find common denominator :-)
alright then :/

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Theres already a common denominator .-.
yep right so we can write it as \[\huge\rm \frac{( 3m-1) -(2m+1)}{ m-2 }\] now distribute parenthses by negative |dw:1432871986273:dw|
(3m-1)(-2m-1) / m-2 right ?
No wait we take out the parentheses
are you trolling us, pooja?
?
yes right after u distribute by negative one you can remove parentheses
Right and then i jst combine like terms right? so then it would be -m/m-2?
hmmm nope \[\huge\rm \frac{ \color{reD}{3m}\color{blue}{-1} \color{reD}{-2m}\color{blue}{ -1} }{ m-2 }\] that's what you got after distributed by negative now combine like terms
oo so m/m-2 right ? :)
mhmhm nai mi hermana ;) 3m - 2m = ? -1-1 = ?
0 ? :/ nnesha ye saab bakwaas hai ;-;
lol >.< it's not bakwaas ;-; so final answer 0 ?
No m/m-2
alright red part are like terms and blue one hmmm nope \[\huge\rm \frac{ \color{reD}{3m}\color{blue}{-1} \color{reD}{-2m}\color{blue}{ -1} }{ m-2 }\] 3m-2m = (3-2)m = 1m -1-1= -2 \[\huge\rm \frac{ \color{reD}{m}\color{blue}{-2} \color{reD}{}\color{blue}{ } }{ m-2 }\] 1m is same as m what's next ?? o^_o
it cancels out? so the answer is 0??????
No wait 1?
yep it cancels out but not 0 yep 1 !!!
gO_Od job!! :-)
Yes! thanks nnesha :3
my pleasure :-)

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