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cutiecomittee123

  • one year ago

How do I find the coordinates of the vertex of a parabola? Also How do I find the Foci?

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  1. CoconutJJ
    • one year ago
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    Complete The Square Method.

  2. hwyl
    • one year ago
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    the vertex is the highest or the lowest point of a parabola in the form \(f(x) = a(x-h) + k \) (h, k) is the vertex on condition that a is not equal to zero

  3. Loser66
    • one year ago
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    What is the parabola form? particular problem, please

  4. cutiecomittee123
    • one year ago
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    OMG wow I meant to say hyperbola

  5. CoconutJJ
    • one year ago
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    well that's a different story...

  6. cutiecomittee123
    • one year ago
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    and the equation given is x^2/16 - y^2/25 =1

  7. CoconutJJ
    • one year ago
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    I don't think there is a vertex...

  8. cutiecomittee123
    • one year ago
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    well there are vertices

  9. cutiecomittee123
    • one year ago
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    because with a hyperbola there are basically two parabolas

  10. CoconutJJ
    • one year ago
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    dy/dx*

  11. Loser66
    • one year ago
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    YOur hyperbola has the form \(\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1\) where \(a^2 = 16\) and \(b^2 = 25\)

  12. Loser66
    • one year ago
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    hence, its graph is |dw:1432872366397:dw|

  13. Loser66
    • one year ago
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    Foci will lie on x-axis, and it is calculated by \(c^2 = a^2+b^2 = 16+25 =41\) hence, foci are \((\pm \sqrt {41},0)\)

  14. Loser66
    • one year ago
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    One more thing: it doesn't have directrix but the center, and you know how to find the center, right? just (0,0)

  15. cutiecomittee123
    • one year ago
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    Wait no, how is the center found??

  16. Loser66
    • one year ago
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    half way of foci, in this case, it is ALWAYS =(0,0)|dw:1432873065615:dw|

  17. cutiecomittee123
    • one year ago
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    how do i find the vertices? @Loser66

  18. Loser66
    • one year ago
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    what??? the vertices is a on your expression

  19. anonymous
    • one year ago
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    can you help me with some math

  20. anonymous
    • one year ago
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    i will help you too ok

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