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The x coordinate of the vertex can be found by using the formula -b/2a for a quadratic in standard form.
And the y coordinate from substituting that value back in for x and solving for y.
So, what do you get for the x coordinate of the vertex?
i am stil not sure @JoannaBlackwelder
Can you identify a, b, and c?
ax^2 + bx + c
So, a is 1, b is 2, and c is -3
Do you see how I got those numbers?
i think so
They are the coefficients of each term in the quadratic.
So, can you try to plug those numbers into the formula I gave?
ax^2 + bx + c = 1x^2 + 2x + -3
So, that is the expression given in the problem. Do you see how that is the same?
The formula I was meaning is the -b/2a for the x coordinate of the vertex.
So, that simplifies to -1
And that is the x coordinate of the vertex. :-)
Now we need to find the y coordinate to find the specific point.
We do that by subbing in the -1 into x into the expression.
(-1)^2 + 2(-1) - 3
See how I did that?
:-) So, what does that simplify to?
Right! So, what is the coordinate of the vertex?
Sweet. So, is that above, below, or on the axes?
Thanks so much!