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anonymous

  • one year ago

Easy question for quick medal... help please.

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  1. anonymous
    • one year ago
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    There are (3^2)^4 ⋅ 3^0 bacteria in a petri dish. What is the total number of bacteria in the dish?

  2. Curry
    • one year ago
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    6561

  3. Nnesha
    • one year ago
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    anything to the 0 power is just equal to 1 \[(2)^0 = 1\] \[(x)^0 =1\] another exponent rule \[\huge\rm (x^m)^n = x^{m \times n}\]

  4. anonymous
    • one year ago
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    yeah I remember that .. @Nnesha

  5. anonymous
    • one year ago
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    @Curry that isnt right D:

  6. Curry
    • one year ago
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    well 9^4 * 1 = 6561

  7. Curry
    • one year ago
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    unless i misunderstood that?

  8. anonymous
    • one year ago
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    I think you did unfort! I can give you the answer choices? But I'd like to see the work done with it ..

  9. anonymous
    • one year ago
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    A) 3^8 B) 3^9 C)3^11 D)3^24

  10. Curry
    • one year ago
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    3^2 = 9 = 3 * 3 9^4 = 9*9*9*9 = 6561

  11. Curry
    • one year ago
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    well, if the base number is 3, then it'd just be 3^(2*4) = 3^8

  12. anonymous
    • one year ago
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    Ok thanks!

  13. Nnesha
    • one year ago
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    \[\huge\rm (x^m)^n = x^{m \times n}\] ^^^ multiply outside exponent by inside exponent of the # :-) remember :?? :3 o^_^o btw welcome to openstudy!

  14. anonymous
    • one year ago
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    That would give me (3^8) ⋅ 3^0 @Nnesha right?

  15. Nnesha
    • one year ago
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    yep right and what's 3^0 = ?

  16. anonymous
    • one year ago
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    1?

  17. Nnesha
    • one year ago
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    perfect!

  18. anonymous
    • one year ago
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    @Nnesha ahh then what would the answer be? im a little confused. is 3^8 right?

  19. Nnesha
    • one year ago
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    did you get 3^8 ?

  20. anonymous
    • one year ago
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    OH

  21. anonymous
    • one year ago
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    i see

  22. anonymous
    • one year ago
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    okay, then 3^8 is right. because (3^8) x 1 = 3^8

  23. Nnesha
    • one year ago
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    yep right

  24. anonymous
    • one year ago
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    ahh thanks

  25. Nnesha
    • one year ago
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    np :-)

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