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anonymous
 one year ago
What is the name of the rule that allows this to be true? And is it actually true?
If b/n = Log[a] then b = Log[a^n]
anonymous
 one year ago
What is the name of the rule that allows this to be true? And is it actually true? If b/n = Log[a] then b = Log[a^n]

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And I guess also, what is the principle here that allows it to be true?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh and does the base make any difference? If b/n = Log_E[a] then b = Log_E[a^n]

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Yep, that is true. It is the exponent rule.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1dw:1432883340617:dw

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1It is true for the same reason that when you raise an exponent to another exponent, they multiply.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Got it, T/Y, So I could just quote 'the exponent rule' as an explanation for where this applies

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1I think the technical name is the logarithmic power rule.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah I see, so Log power rule... if n=3 Log (a^n) = Log(a^3) = Log(a . a . a) = Log(a) + Log(a) + Log(a) = 3 Log(a) and because 1 = 3 Log(a) 1/3 = 3 Log(a) /3 1/3 = Log(a)
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