A 39 gram sample of a substance that's a by-product of fireworks has a k-value of 0.1024. N = N0e -kt N0 = initial mass (at time t = 0) N = mass at time t k = a positive constant that depends on the substance itself and on the units used to measure time t = time, in days Find the substance's half-life, in days. Round your answer to the nearest tenth.

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A 39 gram sample of a substance that's a by-product of fireworks has a k-value of 0.1024. N = N0e -kt N0 = initial mass (at time t = 0) N = mass at time t k = a positive constant that depends on the substance itself and on the units used to measure time t = time, in days Find the substance's half-life, in days. Round your answer to the nearest tenth.

Mathematics
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please help
srry idk this one

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the equation is \[\frac{N(t)}{N_o} = e^{-kt}\] set N /No to 1/2 and that is what half life means, the time for the amount to halve \[\frac{1}{2} = e^{-0.1024T}\] take logs and solve for T, where t = T is the half life
nice work @IrishBoy123 !
so the answer cause I cant solve it?
i solved for t and its still not it
i think u use t to solve the 1/2 life... yeah?
no, in irish's example: t is the half life
can you find the answer @Jack1 ?
yeah, i have the answer, what did u get for t?
like 6.790
yep, same here, exact answer for half life is t=6.76902 ish
all i have is grams tho, i don't know the units of k, so i have no idea of the units of t or if k and t are both in the same units of measure...?
(eg if k's relates to pounds/second or something and our No is in grams we have a problem)
so you think you can solve it?
lol... wat? so 6.8 isnt ur answer? (rounded to the nearest tenth)
lol it is now my computer got messed up so it was saying everything incorrect thanks @Jack1
ha. s'cool ;)

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