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review some basics
|dw:1432906516081:dw|

That's a good graph. I get that for the most part...but I have no idea how to verify identities

@B_O_R_E_D Are you familiar with the basic identities?

sort of-ish...they are confusing

Can you post what you know? We'll see if you have everything you need.

hang on

Sorry, I was expecting you to type what YOU know, not what's online.

its not online its just a word doc...I can type if youd like

okay...hang on I'll type it

Yes, it would be nice. Because typing them out also helps you getting familiar with them.

|dw:1432907494538:dw|

reciprocal identities

Did you miss out anything?
There is at least one more that you need.

tan(theta) = sin(theta)/cos(theta) (Tan identity)
cot(theta) = cos(theta)/sin(theta) (Cot Identity)

Good, we'll need these
and... one more...

that's all I've learned

ummm sin(theta)/tan(theta)?

Think Pythagoras's theorem!

SOHCAHTOA

???

hang on

I really have no idea... ummm did I miss cos?

more hint:
|dw:1432904684712:dw|
Pythagoras theorem says \(a^2+b^2=c^2\)

yes I know that

But now you understand why this is true?

yeah more or less

im leaning toward less

okay...so I know we have to use a reciprocal identity

okay....

If we can show that the left side is identical to the right, we're done.

Exactly, that's an excellent start.
A lot of the time, this strategy works!!!

yay!!
okay so
csc(theta) - 1/csc(theta) = cot(theta) cos(theta)

I don't see your reasoning, can you explain?

I replaced sin...so I was just filling that in the equation

Are you at ease with adding fractions, such as 1/3 + 3?

oh! I put it on the wrong side
yeah those are fine

1/3-3 = 1/3 - 3^2/3 = (1-3^2)/3
Does this make sense to you?

okay....
oh yes! I see what you did okay

umm okay...

R U stuck or R U working on it?

trying to work on it...but im still stuck

okay....so that's how you verify it?

csc(x) - sin(x) = 1?

Anyway, from the identity
\(sin^2(x)+cos^2(x)=1\)
we conclude:
\(1-sin^2(x)=cos^2(x)\)

Does that help?

ohhhh...oops sorry... OHHH!!! I get it! yes that helps a lot!

Thank you so much for your help/time!!

okay thank you. I think I can do that...
I have to go, but thank you again!

You're welcome! :)