anonymous
  • anonymous
PLS HELP FAN AND MEDAL ANSWER NEEDS TO BE A FRACTION http://static.k12.com/bank_packages/files/media/mathml_33de3e51fb47e878a0715a5f4c52ffcdd75c0529_1.gif
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
PLS
anonymous
  • anonymous
I IN HURRY
anonymous
  • anonymous

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

hockeychick23
  • hockeychick23
alright, so first we make them into improper fractions: -1 2/3= -5/3 -2 1/3= -7/3 -5/3+7/3= 2/3
anonymous
  • anonymous
ok
anonymous
  • anonymous
i understand that
anonymous
  • anonymous
so anwer is 2/3?
hockeychick23
  • hockeychick23
yes
anonymous
  • anonymous
wow that seems easy
hockeychick23
  • hockeychick23
yep :)
anonymous
  • anonymous
\[-\left[\begin{matrix}2 & 1 \\ & 3\end{matrix}\right]\] = \[-\frac{ 7 }{ 3 }\]
anonymous
  • anonymous
???
anonymous
  • anonymous
cant do negatives as answer has to be positive
anonymous
  • anonymous
im going with 2/3
anonymous
  • anonymous
yeahh thats the answer but i am showing u the workings
anonymous
  • anonymous
oh ok

Looking for something else?

Not the answer you are looking for? Search for more explanations.