where is the vertex of the parabola? y=x^2+2x+3 a. above the x-axis b. on the x-axis c. on the y-axis d. below the x-axis

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where is the vertex of the parabola? y=x^2+2x+3 a. above the x-axis b. on the x-axis c. on the y-axis d. below the x-axis

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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first you need to recognise this in the form y = ax^2+bx +c write down the values of a, b & c then you need to evaluate the expression -b/2a that will give you the x ordinate of the vertex. Put that value of x into your original equation to get the value of y at the vertex from those 2 values x and y you can answer the question
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