If 4.88 grams of Zn reacts with 5.03 grams of S8 to produce 6.02 grams of ZnS, what are the theoretical yield and percent yield of this reaction? Be sure to show the work that you did to solve this problem.
unbalanced equation: Zn + S8 yields ZnS
Someone please help me!!!

- anonymous

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- JFraser

first and most important, balance the equation

- JoannaBlackwelder

Yep, @JFraser is right. Do you know how to balance, @firesquad ?

- anonymous

Balanced equation: 8Zn + S8 ---> 8ZnS

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## More answers

- anonymous

@JFraser @JoannaBlackwelder

- JoannaBlackwelder

Yep, good. Percent yield = (actual/theoretical)*100

- JoannaBlackwelder

Actual is the amount of product given in the problem.

- JoannaBlackwelder

Theoretical is the amount of product found using stoichiometry from the amount of reactant given.

- JoannaBlackwelder

*from the amount of limiting reactant

- anonymous

I am stuck right here
4.88 g Zn x (1 mol Zn/ 65.38 g Zn) = 0.07464 mol Zn
5.03 g S8 x (1 mol S8/ 256.48 g S8) = 0.01961 mol S8

- JoannaBlackwelder

Ok, now use the molar ratios from the balanced reaction to convert to moles of ZnS

- anonymous

what do i do after

- JoannaBlackwelder

For both calculations.

- anonymous

would the ratio be 1: 8

- JoannaBlackwelder

For S8:ZnS, yes

- JoannaBlackwelder

But not for Zn:ZnS

- anonymous

0.07464 mol Zn * (1/1)= 0.07464 mol Zn
0.01961 mol S8 * (8/1) = 0.1569 mol S8
is that how to do it

- JoannaBlackwelder

Well, that looks good for everything but the units at the end.

- anonymous

What do I have to change for the units?

- JoannaBlackwelder

0.07464 mol ZnS
0.1569 mol ZnS

- JoannaBlackwelder

See why I did that?

- anonymous

Oh Ok, now I find the percent yield right?

- JoannaBlackwelder

Well, we need to first determine which value of product to go with.

- JoannaBlackwelder

This is the limiting reactant part. Do you know how to determine that?

- anonymous

The limiting reactant is S8

- JoannaBlackwelder

No, the limiting reactant is the reactant that produces less product.

- anonymous

Sorry, it is Zn

- JoannaBlackwelder

Right :-)

- JoannaBlackwelder

So, what is the mass of product using the limiting reactant?

- anonymous

Sorry for wait I had to do something. It is 0.07464 mol ZnS

- JoannaBlackwelder

No worries. That is the moles of product. What is the mass of product?

- anonymous

65.38 g Zn

- JoannaBlackwelder

Hm, that's not what I get. How did you do that?

- anonymous

I got it from the first formula

- JoannaBlackwelder

Hm, let me show you how I would do this step:
0.07464 mol ZnS(97.44 g/1 mol) = ? g ZnS

- anonymous

Ok I get it

- JoannaBlackwelder

:-) So, can you find the percent yield?

- anonymous

Wait 7.27 is the theoretical yield

- JoannaBlackwelder

Yep

- anonymous

so what is the actual yield?

- JoannaBlackwelder

The amount of product given in the problem.

- anonymous

Thank you so much

- JoannaBlackwelder

You're welcome! :-)

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