anonymous
  • anonymous
If 4.88 grams of Zn reacts with 5.03 grams of S8 to produce 6.02 grams of ZnS, what are the theoretical yield and percent yield of this reaction? Be sure to show the work that you did to solve this problem. unbalanced equation: Zn + S8 yields ZnS Someone please help me!!!
Chemistry
chestercat
  • chestercat
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JFraser
  • JFraser
first and most important, balance the equation
JoannaBlackwelder
  • JoannaBlackwelder
Yep, @JFraser is right. Do you know how to balance, @firesquad ?
anonymous
  • anonymous
Balanced equation: 8Zn + S8 ---> 8ZnS

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anonymous
  • anonymous
JoannaBlackwelder
  • JoannaBlackwelder
Yep, good. Percent yield = (actual/theoretical)*100
JoannaBlackwelder
  • JoannaBlackwelder
Actual is the amount of product given in the problem.
JoannaBlackwelder
  • JoannaBlackwelder
Theoretical is the amount of product found using stoichiometry from the amount of reactant given.
JoannaBlackwelder
  • JoannaBlackwelder
*from the amount of limiting reactant
anonymous
  • anonymous
I am stuck right here 4.88 g Zn x (1 mol Zn/ 65.38 g Zn) = 0.07464 mol Zn 5.03 g S8 x (1 mol S8/ 256.48 g S8) = 0.01961 mol S8
JoannaBlackwelder
  • JoannaBlackwelder
Ok, now use the molar ratios from the balanced reaction to convert to moles of ZnS
anonymous
  • anonymous
what do i do after
JoannaBlackwelder
  • JoannaBlackwelder
For both calculations.
anonymous
  • anonymous
would the ratio be 1: 8
JoannaBlackwelder
  • JoannaBlackwelder
For S8:ZnS, yes
JoannaBlackwelder
  • JoannaBlackwelder
But not for Zn:ZnS
anonymous
  • anonymous
0.07464 mol Zn * (1/1)= 0.07464 mol Zn 0.01961 mol S8 * (8/1) = 0.1569 mol S8 is that how to do it
JoannaBlackwelder
  • JoannaBlackwelder
Well, that looks good for everything but the units at the end.
anonymous
  • anonymous
What do I have to change for the units?
JoannaBlackwelder
  • JoannaBlackwelder
0.07464 mol ZnS 0.1569 mol ZnS
JoannaBlackwelder
  • JoannaBlackwelder
See why I did that?
anonymous
  • anonymous
Oh Ok, now I find the percent yield right?
JoannaBlackwelder
  • JoannaBlackwelder
Well, we need to first determine which value of product to go with.
JoannaBlackwelder
  • JoannaBlackwelder
This is the limiting reactant part. Do you know how to determine that?
anonymous
  • anonymous
The limiting reactant is S8
JoannaBlackwelder
  • JoannaBlackwelder
No, the limiting reactant is the reactant that produces less product.
anonymous
  • anonymous
Sorry, it is Zn
JoannaBlackwelder
  • JoannaBlackwelder
Right :-)
JoannaBlackwelder
  • JoannaBlackwelder
So, what is the mass of product using the limiting reactant?
anonymous
  • anonymous
Sorry for wait I had to do something. It is 0.07464 mol ZnS
JoannaBlackwelder
  • JoannaBlackwelder
No worries. That is the moles of product. What is the mass of product?
anonymous
  • anonymous
65.38 g Zn
JoannaBlackwelder
  • JoannaBlackwelder
Hm, that's not what I get. How did you do that?
anonymous
  • anonymous
I got it from the first formula
JoannaBlackwelder
  • JoannaBlackwelder
Hm, let me show you how I would do this step: 0.07464 mol ZnS(97.44 g/1 mol) = ? g ZnS
anonymous
  • anonymous
Ok I get it
JoannaBlackwelder
  • JoannaBlackwelder
:-) So, can you find the percent yield?
anonymous
  • anonymous
Wait 7.27 is the theoretical yield
JoannaBlackwelder
  • JoannaBlackwelder
Yep
anonymous
  • anonymous
so what is the actual yield?
JoannaBlackwelder
  • JoannaBlackwelder
The amount of product given in the problem.
anonymous
  • anonymous
Thank you so much
JoannaBlackwelder
  • JoannaBlackwelder
You're welcome! :-)

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