Describe the balance of forces that hold together the nuclei of atoms. What happens when these forces get out of balance? **Not sure how to explain this! Thank you:)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Describe the balance of forces that hold together the nuclei of atoms. What happens when these forces get out of balance? **Not sure how to explain this! Thank you:)

Physics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

the force which is acting among protons and neutrons, is the so called strong nuclear force. Such force can be explained, introducing a particle mediator of that nuclear force. Such mediator particle, is the pi meson (pion) , whose mass is about 140 MeV. In other words, as electromagnetic force is due to the mediator which is the photon, in the same way the nuclear force is due to an exchange, among the nucleons, of a pion, or meson pi, in fact the nuclear force is described inside a theory which is calle OPEP namely One Pion Exchange Potential
ohhh okay! and so when they get out of balance, what happens? :/
when a nucleon, for example a proton, is out of the range of the nuclear force, then on it will act the electrostatic force, so it will repelled by other protons. When a neutron is out of the range of a nuclear force, then that nucleus will become instable

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

the nuclear force, acting among nucleons, is very attractive, nevertheless its range it is very short, that range is about 10^-14 cm
ohhh okay! thank you!! :D
and so this problem is complete? :O
yes! I think so! If you want I can give you a simple computation, of the range of the strong nuclear force
ok!
keep in mind that the mediator particle, namely the pion or pi meson , was introduced by the famous physicist Hideki Yukawa (Japan) in the past 1934
Now, we can consider the pion a so called "virtual particle". It is virtual not, because it doesn't exist, it is called virtual because its existence violates the Heisenberg's Uncertainty Principle
Oh! Okay:)
so, we can write this equation: \[\Large \Delta E\Delta t \leqslant \hbar \] it is the violation of the Heisenberg's Uncertainty Principle, as you can see
Now, we can replace \Delat E, with the mass of the pion, namely: \[\Large \Delta E = {M_\pi }{c^2} = 140MeV\]
oohhh okay!
then we can solve that equation for \Delta t, being \Delta t the existence time of the pion, so we get: \[\Large \Delta t \simeq \frac{\hbar }{{140}}\]
Now, since the velocity of the pion is close to the light speed, then we can find the spoace traveled by our pion, using this formula: \[\Large d = c\Delta t = \frac{{\hbar c}}{{140}} = \frac{{197}}{{140}} = 1.4fm\] being \[\Large \hbar c = 197MeV \cdot fm\] and \[\Large 1fm = {10^{ - 13}}cm\] fm=fermi
ohh okay!! :O
thank you!!
thank you!!

Not the answer you are looking for?

Search for more explanations.

Ask your own question