RebeccaPink6398
  • RebeccaPink6398
can someone please help? <3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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RebeccaPink6398
  • RebeccaPink6398
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RebeccaPink6398
  • RebeccaPink6398
please help @BlossomCake @Butterfield1215 @geerky42 @Here_to_Help15 @iYuko @Legends @Nnesha @omarbirjas @ryamorgan284 @sammixboo @tHe_FiZiCx99 @TheSmartOne @ElmosGuts @iambatman @barbdewysveck1 @ganeshie8 @iGreen @LegendarySadist @Michele_Laino @robtobey @Vocaloid @welshfella @10115658 @1351250faith @31356 @563blackghost @Abaker32 @Afrodiddle @AkashdeepDeb @amistre64 @angelv00 @appleboy2 @AravindG @ard456 @background43 @baseballer2014 @bella5 @BOSSKID @k_lynn @brownalex976 @bruhhh @Bungun1234321 @Butterfield1215 @butterflydreamer @chelseydesoto
welshfella
  • welshfella
this is not too hard - add up all the fractions then subtract 10 from the result

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RebeccaPink6398
  • RebeccaPink6398
I made then in like numbers and did it and i got 51 but i dont know how to make it back into fractions or if i was supposed to do that
anonymous
  • anonymous
I'll re-write the left side to make it a little easier \[(6+5+2)+(\frac{ 1 }{ 5 }+\frac{ 4 }{ 5 })+(\frac{ 1 }{ 2 })\]
RebeccaPink6398
  • RebeccaPink6398
ohh um (13)+5/5 or 1 whole+ half sooo 14.5?
anonymous
  • anonymous
Right, so we have \[14\frac{ 1 }{ 2 }=n+10\] Now just subtract the 10
RebeccaPink6398
  • RebeccaPink6398
A!!! :D yay thank you
anonymous
  • anonymous
Yep, it would be A. And no problem :)
TheSmartOne
  • TheSmartOne
@RebeccaPink6398 Do not tag a lot of people, that is considered mass tagging and you can get a nice susepension for continuing to do the same thing.

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