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anonymous
 one year ago
What is the vertical asymptote for the graph of
y = x2/(x2)(x+3)?
anonymous
 one year ago
What is the vertical asymptote for the graph of y = x2/(x2)(x+3)?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think that its x=3 and x=2 ? right?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1There is an ambiguity with the rational function, not sure if it is \(\large y = \frac{x2}{(x2)(x+3)}\) or \(\large y = \frac{(x2)}{(x2)}(x+3)\) According to the rule PEMDAS, it's the second, but I think you meant the first.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Hint: simplify the rational function before attempting to locate asymptotes.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's the first equation

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Good, so follow the hints and see where they take you!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I did simplify thats how I got x = 3

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1What is the simplified version of the function, and what do you think the graph looks like?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think there is a hole so the answer might be (2, 1/5) ?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Very good, the hole is at (2,1/5). Where do you think the asymptotes are?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1The function is now: f(x)=1/(x+3) where x\(\ne\)2 the hole (x=2) is not part of the domain.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1hint: Try to visualize where the asymptotes should be. If not ,use your graphs calculator

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Remember that an asymptote occurs when the denominator becomes zero.
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