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theopenstudyowl

  • one year ago

Was wondering if someone could go over these homework answers with me before I turn this in.

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  1. theopenstudyowl
    • one year ago
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    Which of the following represents the information you need in order to find the sample size necessary for a confidence interval for a single population proportion with a given margin of error and confidence level? z*, n, t*, m, p* t*, n, p* z*, m, p* z*, m, s

  2. theopenstudyowl
    • one year ago
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    I think it's C

  3. Michele_Laino
    • one year ago
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    sorry can you write the meaning of z, m, s, t, p?

  4. theopenstudyowl
    • one year ago
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    sure, one sec...

  5. theopenstudyowl
    • one year ago
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    Z or z refers to a standardized score, also known as a z score.

  6. Michele_Laino
    • one year ago
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    ok!

  7. theopenstudyowl
    • one year ago
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    its ok, I think I known the answe to this one, could I ask another one in the same thread??

  8. Michele_Laino
    • one year ago
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    ok!

  9. theopenstudyowl
    • one year ago
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    A company wants to find out what kinds of transportation its employees use to get to work. It conducts a survey of 537 employees, and 243 say they ride the bus. Construct a 95% confidence interval for the proportion of employees who ride the bus to and from work. (.411, .495) (.4521, .4539) (2.168, 2.252) (.3962, .5098) (.4316, .4744) I think it's C

  10. anonymous
    • one year ago
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    I'm sure it's b

  11. theopenstudyowl
    • one year ago
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    prove it

  12. Michele_Laino
    • one year ago
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    we have a probability 243/537 for going with bus, and a probability of 1-(243/537) for not going with bus

  13. Michele_Laino
    • one year ago
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    oops...1- (243/537)

  14. Michele_Laino
    • one year ago
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    I think that we have to use the binomial distribution

  15. Michele_Laino
    • one year ago
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    so the standard deviation is: \[\Large \sigma = \sqrt {Npq} = \sqrt {537\frac{{243}}{{537}}\left( {1 - \frac{{243}}{{537}}} \right)} = ...\]

  16. Michele_Laino
    • one year ago
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    whereas the mean is: \[\Large m = Np = 243\]

  17. Michele_Laino
    • one year ago
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    then we can write: \[\begin{gathered} m = Np = 243 \hfill \\ \hfill \\ \sigma = 11.534 \hfill \\ \end{gathered} \]

  18. theopenstudyowl
    • one year ago
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    ok

  19. Michele_Laino
    • one year ago
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    next, a confidence level of 95% mean a distance about 1.96* sigma

  20. theopenstudyowl
    • one year ago
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    oh ok

  21. theopenstudyowl
    • one year ago
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    I think my answer is right! Thanks

  22. Michele_Laino
    • one year ago
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    ok! Thanks!

  23. theopenstudyowl
    • one year ago
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    is it right?

  24. theopenstudyowl
    • one year ago
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    did u get the same result?

  25. Michele_Laino
    • one year ago
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    please I continue then

  26. theopenstudyowl
    • one year ago
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    ok

  27. theopenstudyowl
    • one year ago
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    sorry

  28. Michele_Laino
    • one year ago
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    referring to our sample of population, we have: mean value= 243/537=0.452 and 1.96*sigma= 1.96*(11.534/537)=0.04 so our interval, is: 0.452-0.04=0.412 left value 0.452+0.04= 0.492 right value, or \[\Large \left( {0.412,\quad 0.492} \right)\]

  29. theopenstudyowl
    • one year ago
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    huh, looks like the closest answer is A???

  30. Michele_Laino
    • one year ago
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    yes!

  31. theopenstudyowl
    • one year ago
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    wow! thanks! And thnxs for walking me through the steps

  32. Michele_Laino
    • one year ago
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    thanks! :)

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