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anonymous
 one year ago
need help with a couple of algebra questions.
Will fan and Medal!
anonymous
 one year ago
need help with a couple of algebra questions. Will fan and Medal!

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JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Ok, what are your questions?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.09x^2  16x + 60 = 0 Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (3 points)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do you determine the radicand?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0That is the part in the quadratic equation that is under the radical. b^24ac

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so you would just plug in and solve?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Yep. If the radicand is positive, that means that the solution(s) will be two real solutions.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0If it is 0, then the solution is one real solution.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0And if it is negative, there will be two imaginary solutions.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0So, what do you get?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Hm, that's not what I get. Check your signs.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I will show you my work

anonymous
 one year ago
Best ResponseYou've already chosen the best response.09x^216x+60=0 16^24(9)(60) 16^24(540) 2562160 1904

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Yep, that's what I get. :)

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0So, what type are the solutions?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, so that would be the radicand?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Solve 4x2 + 8x  5 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used. (4 points)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I chose to solve by completing the square but I forgot how to solve it can you help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have a really bad memory:(

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Hm, you can do it that way, but I think the quadratic formula would be easier.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am looking at the steps from this link http://assets.openstudy.com/updates/attachments/5567650be4b01de5673a8a96vocaloid1432844914043screenshot20150528at4.28.10pm.png

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would it be okay if I had a negative for c instead of a positive?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you still there?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0At that link, you just need the step on the bottom right. The rest is deriving the formula.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0And any of the terms can be positive or negative :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432923772865:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is what I have. What do I do now?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0No, that's not what I get. Check your signs under the radical.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I will show you my work

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432923987899:dw

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432924306758:dw Very close though!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432924501938:dw so it would be this

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Yep, but that can simplify more.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got 4/8=0.5 and 20/8=2.5

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Yep, awesome! :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0An Labrador leaps over a hurdle. The function f(t) represents the height of the Labrador above the ground, in inches, at t seconds: f(t) = 16t2 + 26t A foxhound jumps over the same hurdle. The table shows the height of the foxhound above the ground g(t), in inches, at t seconds: Time (t) g(t) 0 0 0.4 5.44 0.6 6.24 0.7 6.16 0.8 5.76 1.0 4 1.2 0 Part A: Compare and interpret the maximum of f(t) and g(t)? (4 points) Part B: Which function has a greater xintercept? What do the xintercepts of the graphs of f(t) and g(t) represent? (4 points) Part C: Determine the yintercepts of both functions and explain what this means in the context of the problem. (2 points)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is what I got Part A: The max of g(t) occurs when t=0.6 seconds, for f(t) since the parabola is concave down due to the negative sign. Then we know that there is a max on the parabola, the max for f(t) occurs at (13/16,169/16) 169/6=10.5625 inches at time 0.8125 seconds. Part B: The function that has a greater x intercept is f(t), meaning that when the Labrador will land later than the fox when it jumps over the hurdle. Part C: I need help with part c

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0I'll be back on later
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