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Ok, what are your questions?
9x^2 - 16x + 60 = 0 Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (3 points)
how do you determine the radicand?
That is the part in the quadratic equation that is under the radical. b^2-4ac
so you would just plug in and solve?
Yep. If the radicand is positive, that means that the solution(s) will be two real solutions.
If it is 0, then the solution is one real solution.
And if it is negative, there will be two imaginary solutions.
So, what do you get?
Hm, that's not what I get. Check your signs.
I will show you my work
9x^2-16x+60=0 -16^2-4(9)(60) -16^2-4(540) 256-2160 -1904
Yep, that's what I get. :-)
So, what type are the solutions?
ok, so that would be the radicand?
Solve 4x2 + 8x - 5 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used. (4 points)
I chose to solve by completing the square but I forgot how to solve it can you help?
I have a really bad memory:(
Hm, you can do it that way, but I think the quadratic formula would be easier.
I am looking at the steps from this link http://assets.openstudy.com/updates/attachments/5567650be4b01de5673a8a96-vocaloid-1432844914043-screenshot20150528at4.28.10pm.png
would it be okay if I had a negative for c instead of a positive?
are you still there?
At that link, you just need the step on the bottom right. The rest is deriving the formula.
And any of the terms can be positive or negative :-)
this is what I have. What do I do now?
No, that's not what I get. Check your signs under the radical.
I will show you my work
|dw:1432924306758:dw| Very close though!
|dw:1432924501938:dw| so it would be this
Yep, but that can simplify more.
I got -4/8=-0.5 and -20/8=-2.5
Yep, awesome! :D
An Labrador leaps over a hurdle. The function f(t) represents the height of the Labrador above the ground, in inches, at t seconds: f(t) = -16t2 + 26t A foxhound jumps over the same hurdle. The table shows the height of the foxhound above the ground g(t), in inches, at t seconds: Time (t) g(t) 0 0 0.4 5.44 0.6 6.24 0.7 6.16 0.8 5.76 1.0 4 1.2 0 Part A: Compare and interpret the maximum of f(t) and g(t)? (4 points) Part B: Which function has a greater x-intercept? What do the x-intercepts of the graphs of f(t) and g(t) represent? (4 points) Part C: Determine the y-intercepts of both functions and explain what this means in the context of the problem. (2 points)
this is what I got Part A: The max of g(t) occurs when t=0.6 seconds, for f(t) since the parabola is concave down due to the negative sign. Then we know that there is a max on the parabola, the max for f(t) occurs at (13/16,169/16) 169/6=10.5625 inches at time 0.8125 seconds. Part B: The function that has a greater x- intercept is f(t), meaning that when the Labrador will land later than the fox when it jumps over the hurdle. Part C: I need help with part c
I'll be back on later