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Ok, what are your questions?

how do you determine the radicand?

That is the part in the quadratic equation that is under the radical. b^2-4ac

so you would just plug in and solve?

Yep. If the radicand is positive, that means that the solution(s) will be two real solutions.

If it is 0, then the solution is one real solution.

And if it is negative, there will be two imaginary solutions.

So, what do you get?

Hm, that's not what I get. Check your signs.

I will show you my work

Sure :-)

9x^2-16x+60=0
-16^2-4(9)(60)
-16^2-4(540)
256-2160
-1904

Yep, that's what I get. :-)

So, what type are the solutions?

ok, so that would be the radicand?

I chose to solve by completing the square but I forgot how to solve it can you help?

I have a really bad memory:(

Hm, you can do it that way, but I think the quadratic formula would be easier.

ok

would it be okay if I had a negative for c instead of a positive?

are you still there?

At that link, you just need the step on the bottom right. The rest is deriving the formula.

oh ok

And any of the terms can be positive or negative :-)

|dw:1432923772865:dw|

this is what I have. What do I do now?

No, that's not what I get. Check your signs under the radical.

I will show you my work

Sounds good

|dw:1432923987899:dw|

|dw:1432924306758:dw|
Very close though!

|dw:1432924501938:dw|
so it would be this

Yep, but that can simplify more.

I got -4/8=-0.5 and -20/8=-2.5

Yep, awesome! :D

I'll be back on later