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anonymous

  • one year ago

Unit 6 Rational Expression Lesson 6 Adding and subtracting Rational Expression and like denominator. Simplify n - 2 2 - n n - 2 A. 2 -n n + 2 B. -1 C. n + 2 n - 2 D. 1 my answer: C

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  1. anonymous
    • one year ago
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    @Awolflover1 @jagr2713

  2. anonymous
    • one year ago
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    \[\frac{ n }{ 2-n } - \frac{ 2 }{ n-2 }\]

  3. anonymous
    • one year ago
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    Is that your question

  4. anonymous
    • one year ago
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    Yes

  5. anonymous
    • one year ago
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    it would really be helpful if you used the equation tool below fortunately @iambatman is good a mind reading

  6. anonymous
    • one year ago
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    just another superpower i guess

  7. anonymous
    • one year ago
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    I can't is not working on my side

  8. anonymous
    • one year ago
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    \[\huge \frac{ a }{ b }-\frac{ c }{ d } = \frac{ ad-bc }{ bd }\] you could use this property

  9. anonymous
    • one year ago
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    \[\frac{ n(n-2)-2(2-n) }{ (2-n)(n-2) }\]

  10. anonymous
    • one year ago
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    just to get it out there I like that username Batman

  11. anonymous
    • one year ago
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    Just start simplifying now, and thanks haha :)

  12. anonymous
    • one year ago
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    okay ur welcome

  13. anonymous
    • one year ago
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    so it will be A

  14. anonymous
    • one year ago
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    Ehh how did you manage to get that?

  15. anonymous
    • one year ago
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    because I have to cancel out the ( 2 -n) and (n-2) and that what I got

  16. anonymous
    • one year ago
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    \[\frac{ n(n-2)-2(2-n) }{ (2-n)(n-2) } \implies \frac{ n^2-2n-4+2n }{ (2-n)(n-2) }\] right?

  17. anonymous
    • one year ago
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    \[\frac{ n^2-4 }{ (2-n)(n-2) } \implies \frac{ (n-2)(n+2) }{ (2-n)(n-2) } \implies \frac{ n+2}{ 2-n }\]

  18. anonymous
    • one year ago
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    okay cool I have 3 more question it hard multitasking

  19. anonymous
    • one year ago
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    Focus on one question at a time, but if they are similar go over my work and try them out :)

  20. anonymous
    • one year ago
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    okay thanks so much

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