anonymous
  • anonymous
Unit 6 Rational Expression Lesson 6 Adding and subtracting Rational Expression and like denominator. Simplify n - 2 2 - n n - 2 A. 2 -n n + 2 B. -1 C. n + 2 n - 2 D. 1 my answer: C
Algebra
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@Awolflover1 @jagr2713
anonymous
  • anonymous
\[\frac{ n }{ 2-n } - \frac{ 2 }{ n-2 }\]
anonymous
  • anonymous
Is that your question

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anonymous
  • anonymous
Yes
anonymous
  • anonymous
it would really be helpful if you used the equation tool below fortunately @iambatman is good a mind reading
anonymous
  • anonymous
just another superpower i guess
anonymous
  • anonymous
I can't is not working on my side
anonymous
  • anonymous
\[\huge \frac{ a }{ b }-\frac{ c }{ d } = \frac{ ad-bc }{ bd }\] you could use this property
anonymous
  • anonymous
\[\frac{ n(n-2)-2(2-n) }{ (2-n)(n-2) }\]
anonymous
  • anonymous
just to get it out there I like that username Batman
anonymous
  • anonymous
Just start simplifying now, and thanks haha :)
anonymous
  • anonymous
okay ur welcome
anonymous
  • anonymous
so it will be A
anonymous
  • anonymous
Ehh how did you manage to get that?
anonymous
  • anonymous
because I have to cancel out the ( 2 -n) and (n-2) and that what I got
anonymous
  • anonymous
\[\frac{ n(n-2)-2(2-n) }{ (2-n)(n-2) } \implies \frac{ n^2-2n-4+2n }{ (2-n)(n-2) }\] right?
anonymous
  • anonymous
\[\frac{ n^2-4 }{ (2-n)(n-2) } \implies \frac{ (n-2)(n+2) }{ (2-n)(n-2) } \implies \frac{ n+2}{ 2-n }\]
anonymous
  • anonymous
okay cool I have 3 more question it hard multitasking
anonymous
  • anonymous
Focus on one question at a time, but if they are similar go over my work and try them out :)
anonymous
  • anonymous
okay thanks so much

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