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theopenstudyowl
 one year ago
statzzz
theopenstudyowl
 one year ago
statzzz

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theopenstudyowl
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino

theopenstudyowl
 one year ago
Best ResponseYou've already chosen the best response.0I was wondering if you could check my answers...

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2question #4, I got \[\Large \left( {0.7242,\quad 0.8358} \right)\]

nuccioreggie
 one year ago
Best ResponseYou've already chosen the best response.0Solve negative 7 over 3, the whole multiplied by x minus 3 equals negative 52. 21 39 45 59

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2question #9 I got 2401, namely the last option. Please you have to reply, since I can not give you the answer directly

theopenstudyowl
 one year ago
Best ResponseYou've already chosen the best response.0i just got back

theopenstudyowl
 one year ago
Best ResponseYou've already chosen the best response.0and got it and thanks

theopenstudyowl
 one year ago
Best ResponseYou've already chosen the best response.0are you on 10?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2question #10 my definition of error margin m, is: \[m = \frac{{\Delta a}}{a}\] where a is the mean value, and \Delta a is the uncertainty on a

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2how have you defined the error margin?

theopenstudyowl
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino are all the others right?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I'm pondering...

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2for example, in question #3 how do you got 745?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2can you write your steps, in order to get 745?

theopenstudyowl
 one year ago
Best ResponseYou've already chosen the best response.0it was so long ago when I did these i forgot the steps but remembered the ansers that is why im asking for u to check them lol

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2ok! do you remember the definition of error margin?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2question #3 the standard deviation is: 11.534 so the 95% confidence interval is 11.534* 1.65 = 19

theopenstudyowl
 one year ago
Best ResponseYou've already chosen the best response.0ok thnxs sorry for the late reply

nuccioreggie
 one year ago
Best ResponseYou've already chosen the best response.0The graph below shows the prices of different numbers of boots at a store: A graph is shown. The values on the x axis are 0, 2, 4, 6, 8, and 10. The values on the y axis are 0, 25, 50, 75, 100, and 125. Points are shown on ordered pairs 0, 0 and 2, 25 and 4, 50 and 6, 75 and 8, 100. These points are connected by a line. The label on the x axis is Number of Boots. The title on the y axis is Price in dollars. Which equation can be used to determine p, the cost of b boots? p = 12.50b p = 25b b = 25p b = 12.50p

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2question #5 I got 261, namely, close to the first option

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2question #3 I got n=751

theopenstudyowl
 one year ago
Best ResponseYou've already chosen the best response.0nice and thnxs!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2question #6 I think you are right! we have to determine the new proportion

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2question #10 hint: the formula for margin error, is: \[\Large m = {z^*}\sqrt {\frac{{p\left( {1  p} \right)}}{n}} \] where p is the sample proportion, n is the sample size, and z* is the value which comes from the percentage of the confidence level

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2question #7 I got: \[\Large \left( {0.24316,\quad 0.35684} \right)\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2the procedure is the same as in the first exercise, we have to apply the binomial distribution

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2question #8, I got: n= 504.21, so your answer is right!

theopenstudyowl
 one year ago
Best ResponseYou've already chosen the best response.0awesome! thnxs

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2finally, for question #9, I have applied the subsequent formula: \[\Large \frac{{1.96}}{{\sqrt n }} = 0.04\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2our homework is completed!

theopenstudyowl
 one year ago
Best ResponseYou've already chosen the best response.0yah!!1 can u help later? if so, can u give the hours your online

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I will stay here for at least 2 hours

theopenstudyowl
 one year ago
Best ResponseYou've already chosen the best response.0ok cool can u help some more then plz?

theopenstudyowl
 one year ago
Best ResponseYou've already chosen the best response.0one second plz, give me 10 minutes before i upload some more and ty soo much

theopenstudyowl
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino , is #10 right?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2question #10 I give this hint: \[m = {z^*}\sqrt {\frac{{p\left( {1  p} \right)}}{n}} \] m is the margin of error, p is the sample proportion, n is the sample size, and z* is coming from the percentage of confidence level, namely if confidence level is 95%, then z*=1.96, if confidence level is 90%, then z*=1.65

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I think option 3 only
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