anonymous
  • anonymous
matrix equation help? {{12,7},{5,3}}x={{2,-1},{3,2}}
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
an augment might be beneficial
amistre64
  • amistre64
unless you know how to work an inverse? Ax = b A'Ax = A'b Ix = A'b x = A'b
anonymous
  • anonymous
how can i plug in matrices?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
what are you working with? ti83?
anonymous
  • anonymous
No. I meant how can I plug in matrices on Openstudy
anonymous
  • anonymous
So I can show the equation correctly
amistre64
  • amistre64
its labor intensive, but i did make an app for it, if you are using a laptop or desktop that is
amistre64
  • amistre64
http://assets.openstudy.com/updates/attachments/4dfe63b10b8bbe4f12e73631-amistre64-1308517305050-matrix.html
amistre64
  • amistre64
\[\left[ \begin{array}c 12 & 7\\5 & 3\\\end{array} \right] x= \left[ \begin{array}c 2 & -1\\3 & 2\\\end{array} \right]\]
anonymous
  • anonymous
\[\[\left[ \begin{array}c 12 & 7\\5 & 3\\\end{array} \right]\] X = \[\left[ \begin{array}c 2 & -1\\3 & 2\\\end{array} \right]\]\]
anonymous
  • anonymous
hows that?
anonymous
  • anonymous
yeah
amistre64
  • amistre64
it was designed to post one matrix hence the oddity of trying multiples, but knowing the latex sorts it out
amistre64
  • amistre64
so, how do we approach this? inverse are augment? either way is fine. inverse may be simpler in this case tho
amistre64
  • amistre64
we can augment it as this, and row reduce. \[\left[ \begin{array}c 12 & 7 & | & 2 & -1\\5 & 3 & | & 3 & 2\\\end{array} \right]\]
anonymous
  • anonymous
how do you reduce it
amistre64
  • amistre64
elementary row operations for course, get the left side worked into the identity matrix. and the right side works itself into x
amistre64
  • amistre64
divide row1 by 12 and multiply by -5 and add to row2 12,7,2,-1 1,7/12,2/12,-1/12 -5,-35/12,-10/12,5/12 5, 3, 3, 2 -5,-35/12,-10/12, 5/12 5, 36/12, 36/12,24/12 ---------------------- 0, 1/12, 26/12, 29/12 multiply by 12 0, 1, 26, 29 new setup 1, 7/12, 2/12, -1/12 0, 1 , 26 , 29 multiply row 2 by -7/12 and add it to row1 1, 7/12, 2/12, -1/12 0, -7/12 , -26(7)/12 , -29(7)/12 -------------------------------- 1, 0 , -90/6 , -204/12 1, 0 , -15 , -17 1, 0, -15, -17 0, 1, 26, 29 I x
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=rref%7B%7B12%2C7%2C2%2C-1%7D%2C%7B5%2C3%2C3%2C2%7D%7D
amistre64
  • amistre64
did you try for an inverse?
amistre64
  • amistre64
-35 12 7 5 3 36 det = 1 by some basic shortcut, A' has a pattern swap corners and negate the other 2 A' = 3 -7 -5 12

Looking for something else?

Not the answer you are looking for? Search for more explanations.