anonymous
  • anonymous
A phone number contains 7 digits. How many different numbers can be made using the digits 0–9 if the first digit is not 0 and none of the digits can be repeated? a. 362,880 b. 3,780 c. 24
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
beautiful combinations and permutations question
anonymous
  • anonymous
how does that work it's not one of my answers?
anonymous
  • anonymous
if the first digit is not zero, then that leaves 9 possible numbers

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anonymous
  • anonymous
how do i calculate this?
anonymous
  • anonymous
therefore:
anonymous
  • anonymous
9 in the first combination
anonymous
  • anonymous
correctly permutation
anonymous
  • anonymous
|dw:1432926939710:dw| giving 362, 880 posssibilities
anonymous
  • anonymous
this makes no sense
anonymous
  • anonymous
which part?
anonymous
  • anonymous
sorry that should have read 0-9
anonymous
  • anonymous
so what is the answer?
anonymous
  • anonymous
362, 880
anonymous
  • anonymous
think of it as boxes, the first one you have 9 choices (1-9)
anonymous
  • anonymous
the second one you have 8 choices, becuase one has already been selected
anonymous
  • anonymous
now according to the fundamental principle of counting, the optios are 9 x 8 x 7 x 6 etc
anonymous
  • anonymous
you can check with others if you like @Thesmartone
anonymous
  • anonymous
im sorry the answers were, a. 10 × 96 b. 9 × 107 c. 9 × 106 d. 107

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