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anonymous

  • one year ago

A phone number contains 7 digits. How many different numbers can be made using the digits 0–9 if the first digit is not 0 and none of the digits can be repeated? a. 362,880 b. 3,780 c. 24

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  1. anonymous
    • one year ago
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    beautiful combinations and permutations question

  2. anonymous
    • one year ago
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    how does that work it's not one of my answers?

  3. anonymous
    • one year ago
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    if the first digit is not zero, then that leaves 9 possible numbers

  4. anonymous
    • one year ago
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    how do i calculate this?

  5. anonymous
    • one year ago
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    therefore:

  6. anonymous
    • one year ago
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    9 in the first combination

  7. anonymous
    • one year ago
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    correctly permutation

  8. anonymous
    • one year ago
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    |dw:1432926939710:dw| giving 362, 880 posssibilities

  9. anonymous
    • one year ago
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    this makes no sense

  10. anonymous
    • one year ago
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    which part?

  11. anonymous
    • one year ago
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    sorry that should have read 0-9

  12. anonymous
    • one year ago
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    so what is the answer?

  13. anonymous
    • one year ago
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    362, 880

  14. anonymous
    • one year ago
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    think of it as boxes, the first one you have 9 choices (1-9)

  15. anonymous
    • one year ago
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    the second one you have 8 choices, becuase one has already been selected

  16. anonymous
    • one year ago
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    now according to the fundamental principle of counting, the optios are 9 x 8 x 7 x 6 etc

  17. anonymous
    • one year ago
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    you can check with others if you like @Thesmartone

  18. anonymous
    • one year ago
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    im sorry the answers were, a. 10 × 96 b. 9 × 107 c. 9 × 106 d. 107

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