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Given: ΔABC is a right triangle.
Prove: a2 + b2 = c2
The two-column proof with missing justifications proves the Pythagorean Theorem using similar triangles:
Statement
Justification
Draw an altitude from point C to Line segment AB
Let segment BC = a
segment CA = b
segment AB = c
segment CD = h
segment DB = x
segment AD = y
y + x = c
c over a equals a over y and c over b equals b over x
a2 = cy; b2 = cx
a2 + b2 = cy + b2
a2 + b2 = cy + cx
a2 + b2 = c(y + x)
a2 + b2 = c(c)
a2 + b2 = c2

ignore the jerk. And let me read this proof.

What do you think it is hun ?

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SSS theorem would be used to prove s triangles are congruent, are we proving that here @Moo_Moo17 ?

It okay ^^. and I agree, so we know that is not the answer. let's look at the other answer choices.

A. Pieces of Right Triangles Similarity Theorem, what do you think of this answer choice ?

ohhh ok that makes more since now

Awesome ^^.

^-^ ok so with tht one crossed out would it be B since i think the triangle is SSS

isn't which NOT justification for proof?.

yea

Well were no done let's look at answer D. :P

ok (: D looks like it would be good what do u think

Nah if you look at the two column proof Addition Property of Equality work is done .

oh i see what mean so is it C then since D was already solved

C was done in the problem too because B2=cx cx is enter in the place of b2

oh lol ok so um.. with it be B then ?

nah A . since we would need sss to prove congruence and stuff :P

oh ok thank you so much (: do u mind help ing me with a few more??

Np and sure ^^

thank you ^w^ here ill post it another question

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