Law of cosines

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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|dw:1432929186134:dw| I'm looking for angle A.
|dw:1432929324519:dw| OK :p

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Other answers:

that's confusing
i'm confused
@BloomLocke367 for law of cosines, think Pythagoreas Theorem with added power if you want to understand it, that's where to start. if you just want the answer, there will be no limit to the amount of online calculators that will do the work for you. otherwise, you have to walk the long mile.
|dw:1432930383845:dw|
so what exactly do I do with that?
to solve \[a^2 = b^2 + c^2 - 2 \ b \ c \ \cos A\] calculate \[a^2 ,\ b^2, \ c^2 \ and \ 2 bc\] you have all the data cos(A) follows from that
so I have289=484+900-1320cosA
awesome
i agree
now what do I do?
\[1320 \ cosA = 484 + 900 - 289 ;\ \ \ cosA = \frac{484 + 900 - 289}{1320} \]
cos A = ?? if it's not 33.948, you can sack me.
I got 0.829...
good because if cos A = 0.829..., then A = 33.948 [degrees]
how so?
try this https://www.google.co.uk/search?q=google+calculator&rlz=1C5CHFA_enGB524GB524&oq=google+calculator&aqs=chrome..69i57j0j5j0j69i64.6310j0j1&sourceid=chrome&ie=UTF-8
Can you help with some more?
@BloomLocke367 gotta go well done, you can do this stuff easily ciao!

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