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BloomLocke367
 one year ago
Law of cosines
BloomLocke367
 one year ago
Law of cosines

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BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1dw:1432929186134:dw I'm looking for angle A.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1dw:1432929324519:dw OK :p

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1that's confusing

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1@BloomLocke367 for law of cosines, think Pythagoreas Theorem with added power if you want to understand it, that's where to start. if you just want the answer, there will be no limit to the amount of online calculators that will do the work for you. otherwise, you have to walk the long mile.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1dw:1432930383845:dw

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1so what exactly do I do with that?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1to solve \[a^2 = b^2 + c^2  2 \ b \ c \ \cos A\] calculate \[a^2 ,\ b^2, \ c^2 \ and \ 2 bc\] you have all the data cos(A) follows from that

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1so I have289=484+9001320cosA

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1now what do I do?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1\[1320 \ cosA = 484 + 900  289 ;\ \ \ cosA = \frac{484 + 900  289}{1320} \]

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1cos A = ?? if it's not 33.948, you can sack me.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1good because if cos A = 0.829..., then A = 33.948 [degrees]

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1Can you help with some more?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1@BloomLocke367 gotta go well done, you can do this stuff easily ciao!
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