Which number is irrational. A. 0.14 sorry for not knowing math terms and such but there's a bar above the "14" B. 1/3 C. pi 4 D. pi 6

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Which number is irrational. A. 0.14 sorry for not knowing math terms and such but there's a bar above the "14" B. 1/3 C. pi 4 D. pi 6

Mathematics
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Do you know what is an irrational number?
Isn't it a number that can be put in decimal form or percentage form?

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Other answers:

can't*
Oops
In mathematics, many of the questions can be answered correctly if we know the definition of the terms. If we do not know what the terms mean, the question will appear difficult. So the first step is to understand the meaning of the terms. From wiki: "a rational number is any number that can be expressed as the quotient or fraction p/q of two integers, p and q, with the denominator q not equal to zero." " an irrational number is any real number that cannot be expressed as a ratio of integers. Irrational numbers cannot be represented as terminating or repeating decimals."
Are the terms clear to you now?
Somewhat
For example: (not the same as the first option) 0.14 = 14/100 =7/50, so it can be expressed as a fraction. is it rational?
Yes
Right?
Good!
Okay
So a number that can become a Fraction or a decimal correct?
Now the number 0.13333333333... is called a repeting decimal. It can be converted to a fraction as 2/15
All repeting decimals can be converted to a fraction.
Oooookay
So we're looking for a number that can't be turned into a fraction right?
Right! If you need further help, let me know.
Oops
Option C and D were supposed to be 4 to the fourth and 6 to the fourth
I knew there was a typo! So are you all good now?
Yes I think it would be D I don't know if I'm correct though
To avoid communication errors, please give me the answer and not the letter.
Oh okay sorry ^-^
6 to the fourth
You said that repeating decimals can be turned into fractions and A and B are both repeating
And 4 to the fourth is 2
You there?
Hello?
well pi is irrational.... so dividing it by anything results in an irrational number.
Oh sorry
I mistyped earlier
4 and 6 are supposed to be put to the fourth
that's ok... I think there are 2 irrational numbers in your answer choices... they both involve pi...
Yeah as I said C and D aren't supposed to have Pi
They're supposed to be put to the fourth
can you use the draw function to write them
\[\sqrt{4} \sqrt{6}\]
I'll let @mathmate continue to answer this
@TwiztTiez Remember that all integers are rational, because 5 is the same as 5/1, so it can be represented by a fraction. So the 4 choices are: 1.44444444..... (or 1.4 with a rep. dec. bar) 1/3 4^6 6^6 ? That's why I prefer dealing with the actual numbers, not the choice letters.
or rather 1.44444444..... (or 1.4 with a rep. dec. bar) 1/3 4^6 \(\sqrt4 \sqrt6\) which is the same as \(\sqrt{24}\)
Which one of these can you NOT represent by a fraction?
I didn't mean for it to look like they were supposed to multiplied sorry
That's ok, the multiplication is understood. I just used the law of exponents to simplify it.
Well \[\sqrt{4} =2\]
For your information 1.4444444... equals 13/9.
Very good start, continue! So \(\sqrt{4}\sqrt6=2\sqrt{6}\) can you go further?
Yup yup
I'll put it this way, can you represent \(\sqrt6\) by a fraction?
4.8989794
...mathematically exactly?
\[2\sqrt{6}=4.8989794...\]
2.449489742783178.... and this is not exact.
4.898979485566356... and this is not exact.
Well how can I make it exact? Is there a way or am I just being oblivious?
And I don't mean that rudely
Sorry if it came off that way
Well, there is no way to represent a square root in decimal form unless it is a perfect square. What does that mean (in the context of this question)?
4.89897948556635619639456814941178278393189496131334025686539... and this is still not exact!
Oh okay so
\[\sqrt{4}=2\]
That's exact right?
yes, sqrt(4) is rational.
Okay I get it
but is sqrt(6)?
It can be proved mathematically that square root of a number (such as 2, 3, 5,6,...) is not rational unless the number is a perfect square (1,4,9,16,25....)
2.44948974278
So no I don't think so
You can read more about it (and it is interesting reading for general information) at, for example, Wiki: http://en.wikipedia.org/wiki/Irrational_number or http://www.purplemath.com/modules/numtypes.htm
Thanks!
Correct, since sqrt(6) is not rational, so 2sqrt(6) is also not rational. Does that clear things up a little?
It does thanks for the help!
Good, you're welcome! :)

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