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brunsonni

  • one year ago

David kicks a soccer ball off the ground and in the air, with an initial velocity of 35 feet per second. Using the formula H(t)=-16t^2+vt+s, what is the maximum height the soccer ball reaches? A. 17.9 feet B. 18.2 feet C. 18.7 feet D. 19.1 feet Please help, I have more than one question like this and it's a module test, so I can't get it wrong. I don't understand how to do this at all.

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  1. anonymous
    • one year ago
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    v is supposed to be the initial speed of 35 and s is the initial height which is 0, so the equation is \[h(t)=-16t^2+35t\], but that won't work with your options.

  2. welshfella
    • one year ago
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    at height 0 -16t^2 - 35t = 0 - we can convert this to vertex form and find maximum height

  3. brunsonni
    • one year ago
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    @peachpi I still don't understand what I would do after getting that equation, because the one I had was the exact same but I had + s on the end. But what would I do next after getting h(t)=-16t^2+35t?

  4. welshfella
    • one year ago
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    * -16t^2 + 35t = 0

  5. brunsonni
    • one year ago
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    @welshfella would I do -16t^2=0 and -35t=0 now or is that completely wrong

  6. anonymous
    • one year ago
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    Hi @brunsonnie use this, this might help https://mathway.com/

  7. anonymous
    • one year ago
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    You could do t = -b/(2a) to find the time of the max height. t = -35/(2*-16) Then plug that in for the height

  8. welshfella
    • one year ago
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    take out -16 -16[t^2 + 2.1875] = -16[(x - 1.09375)^2 - 1.1964] maxm height = 16 * 1.1964 = 19.14

  9. welshfella
    • one year ago
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    * thats t not x!

  10. welshfella
    • one year ago
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    the 1.1964 comes fro 1.09375^2

  11. brunsonni
    • one year ago
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    Thanks

  12. welshfella
    • one year ago
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    yw

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