anonymous one year ago what is the formula for lateral area of a square pyramid

1. mathstudent55

What are you given?

2. mathstudent55

A square pyramid has 4 sides that are congruent triangles.

3. anonymous

i just want the formula @mathstudent55

4. mathstudent55

Do you know the height of each side, or just the height of the pyramid?

5. anonymous

that is cheating i just want the formula

6. anonymous

is it 2xbxl

7. mathstudent55

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8. mathstudent55

Is b the length of the side of the square base, and l the height of each triangular side?

9. anonymous

you know what forget it sorry but you are not helping me

10. mathstudent55

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11. anonymous

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12. mathstudent55

I can't help you because I still don't understand what info about the pyramid you were given, and the formula is different depending on what info you are given.

13. mathstudent55

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14. mathstudent55

$$l = \sqrt{\left( \dfrac{s}{2} \right)^2 + h^2}$$ $$A_{one~face} = \dfrac{s \sqrt{\left( \frac{s}{2} \right)^2 + h^2}}{2}$$ $$Lateral~Surface~Area = 4 \times \dfrac{s \sqrt{\left( \frac{s}{2} \right)^2 + h^2}}{2}$$ $$Lateral ~Surface~Area = 2 s \sqrt{\left( \frac{s}{2} \right)^2 + h^2}$$ $$Lateral ~Surface~Area = s \sqrt{s^2 + 4h^2}$$

15. mathstudent55

If you are given the length of the base, s, and the height of each triangular face, l, then the formula is: $$Lateral~Surface~Area = 4 \times \dfrac{s \times l}{2}$$ $$Lateral~Surface~Area = 2sl$$