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anonymous

  • one year ago

what is the formula for lateral area of a square pyramid

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  1. mathstudent55
    • one year ago
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    What are you given?

  2. mathstudent55
    • one year ago
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    A square pyramid has 4 sides that are congruent triangles.

  3. anonymous
    • one year ago
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    i just want the formula @mathstudent55

  4. mathstudent55
    • one year ago
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    Do you know the height of each side, or just the height of the pyramid?

  5. anonymous
    • one year ago
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    that is cheating i just want the formula

  6. anonymous
    • one year ago
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    is it 2xbxl

  7. mathstudent55
    • one year ago
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    |dw:1432934670819:dw|

  8. mathstudent55
    • one year ago
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    Is b the length of the side of the square base, and l the height of each triangular side?

  9. anonymous
    • one year ago
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    you know what forget it sorry but you are not helping me

  10. mathstudent55
    • one year ago
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    |dw:1432934757998:dw|

  11. anonymous
    • one year ago
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    |dw:1432934845064:dw|

  12. mathstudent55
    • one year ago
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    I can't help you because I still don't understand what info about the pyramid you were given, and the formula is different depending on what info you are given.

  13. mathstudent55
    • one year ago
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    |dw:1432934850632:dw|

  14. mathstudent55
    • one year ago
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    \(l = \sqrt{\left( \dfrac{s}{2} \right)^2 + h^2}\) \(A_{one~face} = \dfrac{s \sqrt{\left( \frac{s}{2} \right)^2 + h^2}}{2}\) \(Lateral~Surface~Area = 4 \times \dfrac{s \sqrt{\left( \frac{s}{2} \right)^2 + h^2}}{2}\) \(Lateral ~Surface~Area = 2 s \sqrt{\left( \frac{s}{2} \right)^2 + h^2}\) \(Lateral ~Surface~Area = s \sqrt{s^2 + 4h^2}\)

  15. mathstudent55
    • one year ago
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    If you are given the length of the base, s, and the height of each triangular face, l, then the formula is: \(Lateral~Surface~Area = 4 \times \dfrac{s \times l}{2} \) \(Lateral~Surface~Area = 2sl \)

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