anonymous
  • anonymous
will fan and medal but need help ASAP!
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
A basketball is thrown upwards. The height f(t), in feet, of the basketball at time t, in seconds, is given by the following function: f(t) = -16t^2 + 44t + 12 Which of the following is a reasonable domain of the graph of the function when the basketball falls from its maximum height to the ground? -0.25 < t < 2 0 < t < 3 1 < t < 2.4 1.4 < t < 3
anonymous
  • anonymous
anonymous
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anonymous
  • anonymous
It reaches a maximum height at F(t) = 0 [dont ask me why] so make the function equal to zero and solve for t
anonymous
  • anonymous
0=-16t^2+44t+12
anonymous
  • anonymous
I got 3 and -1/4
anonymous
  • anonymous
my mistake @gabymarie313 , @DanJS had probably worked that out, its at dy/dt=0 that it reaches a maximum height
anonymous
  • anonymous
so how would I solve it?
anonymous
  • anonymous
first we will find it at the bottom i.e. let t=0 f(0)= -16(0)^2 +44 + 12
anonymous
  • anonymous
f(0) = 44 + 12 f(0) = 56
anonymous
  • anonymous
so is the the maximum height?
anonymous
  • anonymous
maximum height occurs where balls stops, ball stops at dy/dt = 0
anonymous
  • anonymous
dy/dt = 2 (-16t) + 44 = -18t + 44
anonymous
  • anonymous
-18t + 44 = 0 -18t = -44 18 t = 44 t=44/18 t = 2.44
anonymous
  • anonymous
I get it now. Thank you for your time.
anonymous
  • anonymous
do you think you can help me with a couple more @BPDlkeme234
anonymous
  • anonymous
go for it!
anonymous
  • anonymous
Matt sells burgers and sandwiches. The daily cost of making burgers is $520 more than the difference between the square of the number of burgers sold and 30 times the number of burgers sold. The daily cost of making sandwiches is modeled by the following equation: C(x) = 2x^2 - 40x + 300 C(x) is the cost in dollars of selling x sandwiches. Which statement best compares the minimum daily cost of making burgers and sandwiches? It is greater for sandwiches than burgers because the approximate minimum cost is $250 for burgers and $292 for sandwiches. It is greater for sandwiches than burgers because the approximate minimum cost is $100 for burgers and $295 for sandwiches. It is greater for burgers than sandwiches because the approximate minimum cost is $295 for burgers and $100 for sandwiches. It is greater for burgers than sandwiches because the approximate minimum cost is $292 for burgers and $250 for sandwiches.
anonymous
  • anonymous
so how would I solve it ?
anonymous
  • anonymous
When I modelled the burgers I got C(burger) = [(burgers sold)^2 - 30(burgers sold)] + $520
anonymous
  • anonymous
this is very similar to the equation for the sandwiches
anonymous
  • anonymous
now, you can put these under each other and solve: C(x) = 2x^2 -40x +30 C(x) = x^2 - 30x +520
anonymous
  • anonymous
now these are two quafratic equations , and will intersect each other
anonymous
  • anonymous
do I solve for x?
anonymous
  • anonymous
or do I use the quadratic formula?
anonymous
  • anonymous
are you still there @BPDlkeme234 ?
anonymous
  • anonymous
do I solve for x or do I use the quadratic formula to solve?
anonymous
  • anonymous

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