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anonymous
 one year ago
will fan and medal but need help ASAP!
anonymous
 one year ago
will fan and medal but need help ASAP!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A basketball is thrown upwards. The height f(t), in feet, of the basketball at time t, in seconds, is given by the following function: f(t) = 16t^2 + 44t + 12 Which of the following is a reasonable domain of the graph of the function when the basketball falls from its maximum height to the ground? 0.25 < t < 2 0 < t < 3 1 < t < 2.4 1.4 < t < 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@BPDlkeme234 @is3535

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It reaches a maximum height at F(t) = 0 [dont ask me why] so make the function equal to zero and solve for t

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my mistake @gabymarie313 , @DanJS had probably worked that out, its at dy/dt=0 that it reaches a maximum height

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so how would I solve it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0first we will find it at the bottom i.e. let t=0 f(0)= 16(0)^2 +44 + 12

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(0) = 44 + 12 f(0) = 56

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so is the the maximum height?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0maximum height occurs where balls stops, ball stops at dy/dt = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dy/dt = 2 (16t) + 44 = 18t + 44

anonymous
 one year ago
Best ResponseYou've already chosen the best response.018t + 44 = 0 18t = 44 18 t = 44 t=44/18 t = 2.44

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I get it now. Thank you for your time.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you think you can help me with a couple more @BPDlkeme234

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Matt sells burgers and sandwiches. The daily cost of making burgers is $520 more than the difference between the square of the number of burgers sold and 30 times the number of burgers sold. The daily cost of making sandwiches is modeled by the following equation: C(x) = 2x^2  40x + 300 C(x) is the cost in dollars of selling x sandwiches. Which statement best compares the minimum daily cost of making burgers and sandwiches? It is greater for sandwiches than burgers because the approximate minimum cost is $250 for burgers and $292 for sandwiches. It is greater for sandwiches than burgers because the approximate minimum cost is $100 for burgers and $295 for sandwiches. It is greater for burgers than sandwiches because the approximate minimum cost is $295 for burgers and $100 for sandwiches. It is greater for burgers than sandwiches because the approximate minimum cost is $292 for burgers and $250 for sandwiches.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so how would I solve it ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When I modelled the burgers I got C(burger) = [(burgers sold)^2  30(burgers sold)] + $520

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is very similar to the equation for the sandwiches

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now, you can put these under each other and solve: C(x) = 2x^2 40x +30 C(x) = x^2  30x +520

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now these are two quafratic equations , and will intersect each other

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or do I use the quadratic formula?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you still there @BPDlkeme234 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do I solve for x or do I use the quadratic formula to solve?
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