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anonymous

  • one year ago

will fan and medal but need help ASAP!

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  1. anonymous
    • one year ago
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    A basketball is thrown upwards. The height f(t), in feet, of the basketball at time t, in seconds, is given by the following function: f(t) = -16t^2 + 44t + 12 Which of the following is a reasonable domain of the graph of the function when the basketball falls from its maximum height to the ground? -0.25 < t < 2 0 < t < 3 1 < t < 2.4 1.4 < t < 3

  2. anonymous
    • one year ago
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    @BPDlkeme234 @is3535

  3. anonymous
    • one year ago
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    @Thesmarterone

  4. anonymous
    • one year ago
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    It reaches a maximum height at F(t) = 0 [dont ask me why] so make the function equal to zero and solve for t

  5. anonymous
    • one year ago
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    0=-16t^2+44t+12

  6. anonymous
    • one year ago
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    I got 3 and -1/4

  7. anonymous
    • one year ago
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    my mistake @gabymarie313 , @DanJS had probably worked that out, its at dy/dt=0 that it reaches a maximum height

  8. anonymous
    • one year ago
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    so how would I solve it?

  9. anonymous
    • one year ago
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    first we will find it at the bottom i.e. let t=0 f(0)= -16(0)^2 +44 + 12

  10. anonymous
    • one year ago
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    f(0) = 44 + 12 f(0) = 56

  11. anonymous
    • one year ago
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    so is the the maximum height?

  12. anonymous
    • one year ago
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    maximum height occurs where balls stops, ball stops at dy/dt = 0

  13. anonymous
    • one year ago
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    dy/dt = 2 (-16t) + 44 = -18t + 44

  14. anonymous
    • one year ago
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    -18t + 44 = 0 -18t = -44 18 t = 44 t=44/18 t = 2.44

  15. anonymous
    • one year ago
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    I get it now. Thank you for your time.

  16. anonymous
    • one year ago
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    do you think you can help me with a couple more @BPDlkeme234

  17. anonymous
    • one year ago
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    go for it!

  18. anonymous
    • one year ago
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    Matt sells burgers and sandwiches. The daily cost of making burgers is $520 more than the difference between the square of the number of burgers sold and 30 times the number of burgers sold. The daily cost of making sandwiches is modeled by the following equation: C(x) = 2x^2 - 40x + 300 C(x) is the cost in dollars of selling x sandwiches. Which statement best compares the minimum daily cost of making burgers and sandwiches? It is greater for sandwiches than burgers because the approximate minimum cost is $250 for burgers and $292 for sandwiches. It is greater for sandwiches than burgers because the approximate minimum cost is $100 for burgers and $295 for sandwiches. It is greater for burgers than sandwiches because the approximate minimum cost is $295 for burgers and $100 for sandwiches. It is greater for burgers than sandwiches because the approximate minimum cost is $292 for burgers and $250 for sandwiches.

  19. anonymous
    • one year ago
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    so how would I solve it ?

  20. anonymous
    • one year ago
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    When I modelled the burgers I got C(burger) = [(burgers sold)^2 - 30(burgers sold)] + $520

  21. anonymous
    • one year ago
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    this is very similar to the equation for the sandwiches

  22. anonymous
    • one year ago
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    now, you can put these under each other and solve: C(x) = 2x^2 -40x +30 C(x) = x^2 - 30x +520

  23. anonymous
    • one year ago
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    now these are two quafratic equations , and will intersect each other

  24. anonymous
    • one year ago
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    do I solve for x?

  25. anonymous
    • one year ago
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    or do I use the quadratic formula?

  26. anonymous
    • one year ago
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    are you still there @BPDlkeme234 ?

  27. anonymous
    • one year ago
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    do I solve for x or do I use the quadratic formula to solve?

  28. anonymous
    • one year ago
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    @Thesmarterone

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