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anonymous

  • one year ago

(please help asap I really am lost on this can someone be a lifesaver) ---------------------------- 1). Solve the linear system: 2x+3y = 3 x - 6y = -6 a. (-9, 5) b. (-6, 3) c. (-3, 1) d. (0,1) --------------------------- 2). Solve the equation: x^2-100 = 0 a. x = 0, 10 b. x = 10, -10 c. x = 0, -10 d. x = 50, -50

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  1. anonymous
    • one year ago
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    @AQ99

  2. Z4K4R1Y4
    • one year ago
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    Second equation: x = 6y – 6 … substitute into first equation: 2(6y – 6) + 3y =3

  3. AQ99
    • one year ago
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    1. D

  4. Z4K4R1Y4
    • one year ago
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    solve for 'y' then slot result in to find' x'.

  5. Z4K4R1Y4
    • one year ago
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    yh

  6. anonymous
    • one year ago
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    so the 1st one is D and the 2nd on solve for y then slot the results in to find x?

  7. Z4K4R1Y4
    • one year ago
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    for the second question you use a method called completing the square.

  8. Z4K4R1Y4
    • one year ago
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    basically you factorise.

  9. anonymous
    • one year ago
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    |dw:1432946503976:dw|

  10. anonymous
    • one year ago
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    |dw:1432946613983:dw|

  11. anonymous
    • one year ago
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    Answer to 1, (0,1)

  12. anonymous
    • one year ago
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    |dw:1432946755324:dw|

  13. anonymous
    • one year ago
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    so answer to 2 is b

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