The function H(t) = -16t^2 + vt + s shows the height H (t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second.
Part A: The projectile was launched from a height of 82 feet with an initial velocity of 60 feet per second. Create an equation to find the time taken by the projectile to fall on the ground. (2 points)
Part B: What is the maximum height that the projectile will reach? Show your work. (2 points)Part C: Another object moves in the air along the path of g(t) = 10 + 63.8t where g(t) is the

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I am super confused, help me out?

well first you need to understand normally
s= displacement,
v = velocity
t = time

Part B; is solved by calculating dh/dt = 0

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