## anonymous one year ago (geometry) Please Help me!!! i need to find how a triangle can use both the Cosine and Sine laws.

1. anonymous

2. anonymous

a/sineA = b/Sine B 10.7/Sin(x) = 8.3/Sine(42) 8.3 x Sine (x) = 10.7 x Sine (42) make sure your calculator in degree mode: 10.7 x Sin(42 ) is approximately 7.16 degrees Sin (x) = 7.16 degrees/8.3 = 0.86 x = $\sin^{-1}( {0.86})$ x = 59.3 degrees

3. anonymous

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