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mathmath333

  • one year ago

Examine the following relation and state if it is a function \(R = \{(2,1),(3,1), (4,2)\}\)

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  1. math&ing001
    • one year ago
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    Only scenario when it's not a function is when a point has two different images like (2,1),(2,3).

  2. mathmath333
    • one year ago
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    so it is a function .

  3. math&ing001
    • one year ago
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    Yeah

  4. mathmath333
    • one year ago
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    :)

  5. math&ing001
    • one year ago
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    =)

  6. zzr0ck3r
    • one year ago
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    technically there is one more property needed to be a function, it is called the "everywhere defined" This just says that everything in the domain must have an associated range value. But you will always have this property if you list the entire relation as ordered pairs.

  7. math&ing001
    • one year ago
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    Yes, but we don't need to mention that since we're talking about a relation. P.S: A relation is always defined by a set of ordered pairs, even when it's not explicitly. Example: the relation > for natural numbers can still be written as (1,0) (2,0) (2,1) (3,0) (3,1) (3,2)....

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