ayyookyndall
  • ayyookyndall
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Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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MeowLover17
  • MeowLover17
Think of the diameter as a line, solve for the midpoint of that line to find the center.
MeowLover17
  • MeowLover17
And the radius is basically the length from the midpoint to the end of the circle, in this case being one of the other coordinates.
MeowLover17
  • MeowLover17
The formula would be

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MeowLover17
  • MeowLover17
http://www.purplemath.com/modules/midpoint.htm here
MeowLover17
  • MeowLover17
Good luck thats all the information i can give.
jim_thompson5910
  • jim_thompson5910
where are you stuck? are you stuck on the formula given on the page MeowLover17 gave you?
ayyookyndall
  • ayyookyndall
Yes, putting it in.
jim_thompson5910
  • jim_thompson5910
P(-10,-2) and Q(4,6) the x coordinates of each point are -10 and 4 add them up: -10+4 = -6 divide the result by 2: -6/2 = -3 so the x coordinate of the midpoint is x = -3 Do the same for the y coordinates to get the y coordinate of the midpoint
jim_thompson5910
  • jim_thompson5910
very good
ayyookyndall
  • ayyookyndall
Thats it for Part A?
jim_thompson5910
  • jim_thompson5910
so that's effectively what this formula \[\LARGE (x_m, y_m) = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)\] is saying "add up the corresponding coordinates and divide by 2 to get the midpoint "
ayyookyndall
  • ayyookyndall
Okay, got it. :-)
jim_thompson5910
  • jim_thompson5910
yes the midpoint of P and Q is the center because P and Q lie on the same diameter |dw:1432945083421:dw|
jim_thompson5910
  • jim_thompson5910
The radius can be found in 2 ways a) find the distance from the midpoint, ie center, to P or Q (pick one) b) find the distance from P to Q, then divide by 2
ayyookyndall
  • ayyookyndall
Which one will be easier?
jim_thompson5910
  • jim_thompson5910
they're about equal in difficulty since you need to use the distance formula either way
ayyookyndall
  • ayyookyndall
I guess lets do A
jim_thompson5910
  • jim_thompson5910
alright, so you can find the distance from the midpoint to P OR find the distance from the midpoint to Q
ayyookyndall
  • ayyookyndall
Find the distance from the midpoint to P
jim_thompson5910
  • jim_thompson5910
use the distance formula \[\large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\] to find the distance from the midpoint (-3,2) to point P(-10,-2)
jim_thompson5910
  • jim_thompson5910
(x1,y1) = (-3,2) (x2,y2) = (-10,-2)
jim_thompson5910
  • jim_thompson5910
good, now take the square root of that
jim_thompson5910
  • jim_thompson5910
so the exact distance is \[\Large \sqrt{65}\] notice how it says "If your answer is not an integer, express it in radical form"
jim_thompson5910
  • jim_thompson5910
"radical" is math term for "square root, cube root, fourth root, etc"
ayyookyndall
  • ayyookyndall
Did I get it right?
ayyookyndall
  • ayyookyndall
Can't I say 8.06
jim_thompson5910
  • jim_thompson5910
8.06 is the approximate distance, but they want the exact form
jim_thompson5910
  • jim_thompson5910
yes that's the radius in exact radical form
ayyookyndall
  • ayyookyndall
Are we done or is there more?
ybarrap
  • ybarrap
|dw:1432944559846:dw|
jim_thompson5910
  • jim_thompson5910
they just want the radius, so we're done
jim_thompson5910
  • jim_thompson5910
|dw:1432945973861:dw|
jim_thompson5910
  • jim_thompson5910
an integer is a whole number (not just any number)
jim_thompson5910
  • jim_thompson5910
example of integers: -3, -22, 5, 8, 0, 157 example of nonintegers: 2.7, 8.5, \(\large \sqrt{15}\), \(\large \pi\)
ayyookyndall
  • ayyookyndall
Oh, I understand. Thank you! ;-)
jim_thompson5910
  • jim_thompson5910
np

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