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h0pe
 one year ago
The House of Lilliput is using RSA encryption to receive secret messages from all the realms. They have published their public encoding exponent e = 37 and their public modulus M = pq = 527.
Break the code: Find their secret decoding exponent d.
h0pe
 one year ago
The House of Lilliput is using RSA encryption to receive secret messages from all the realms. They have published their public encoding exponent e = 37 and their public modulus M = pq = 527. Break the code: Find their secret decoding exponent d.

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ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0Here's a worked example http://en.wikipedia.org/wiki/RSA_(cryptosystem)#A_worked_example

h0pe
 one year ago
Best ResponseYou've already chosen the best response.0I still don't understand...

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0Your goal is to find the inverse of \(37\) in mod \(\phi(527)\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0Solve \[37x \equiv 1 \pmod{\phi(527)}\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0not familiar with euler totient function ?

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0For example, if your message is 2 then d is 2=mod((mod(2^37, 527))^(d) ,527) Here's why: Since c is your encrypted message c=2^37 mod 527 Then since your original message was "2" then the decrypted message is 2 = c^d mod 527 Combine both to get the 1st equation http://www.wolframalpha.com/input/?i=2%3Dmod%28%28mod%282%5E37%2C+527%29%29%5E%28y%29+%2C527%29
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