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Any ideas anyone
For one single spin, what is probability that it stop on A?
Thats what i thought, but wasnt sure
I mean the probability of a single spin resting on B?
OH...1/4 also i believe
Yes, can we say the same thing for C?
So getting A, followed by B, followed by C is a three step experiment, where each step is independent of each other. Under these circumstances, the probability of success in all three steps is the product of the probability of each step.
Product means multiply them together.
I did not meen to say that
This is called the multiplication rule!
so multiply 1/4 to the third power
Is it A
To avoid communication errors, I prefer you to type the answer itself, not the letters. But no, it's not A. Did you multiply together the probabilities of each of the three steps?
Yes and yes A is wrong i think it is 1/64
That's letter B FYI
Am i right
The work you should have shown is 1/4 * 1/4 * 1/4 = 1/64.
oh i did not know i had to show work im really knew to this...also do you know how to medal people? Also was my awnser right
@mathmate Thanks for the help just finished and got a 100% :)
Yes, 1/64 is right. I usually ask for showing work to make sure you're on the right track. Some students guess, and I don't need that for math.
I thought you already gave me a medal, although you don't have to. You would give a medal to someone who gave you help, and you give the medal to show appreciation by giving him/her a medal. You do this by clicking on the blue "best response" button on the right of the receiver's response. BTW, Welcome to Open Study! We're a nice family that you'd enjoy for a long time. Please read the code of conducts, terms and conditions (links at bottom left). Also, be net-aware, do not give out personal information, or traceable information. This is not a dating site, so if someone sends you undesirable messages, click on the "report abuse" button at the bottom of his/her post.
@mathmate can I have question on it? I don't know what is wrong with my logic but no one answer me for my question
@Loser66 yes, please tag me.
No, this kind of problem. I don't have any thing else
The probability to get A is 1/4, sure. But!! to get A at the first spin, it is another topic!!!
@mathmate thanks for the introduction to study island and also thanks for explaining the medals thing.
My argument: at the first spin, we want the outcome is A, that means it is NOT B and NOT C and NOT D as well.
@Loser66 You are right. If you would like to complete the answer, please go ahead. This has to do with the basic axioms of probability.
for B: the probability is 1/4, hence NOT B is 3/4 same as NOT C and NOT D, hence , combine them, to get NOT (B and C and D) = A, the probability to be SURE that is A is (0.75)^3
Exactly. Each of A,B,C,D has equal probability of 1/4 (4*1/4=1).
If you make a single spin, the probability of landing on A is 1/4. Do we agree on this ?
That is my question. What is wrong with it?? to force the first spin is A , we need NOT B and NOT C and NOT D but that argument gives us different result from just pick 1/4 for A
Landing on A implicitly tells us that it is not B, not C and not D. So the conditions are superfluous.
|dw:1432949835677:dw| A,B,C,D are mutually exclusive and complementary.
So if you specify A, automatically it excludes the others.
AAAhh, I got you!!! "EXCLUSIVE" thanks for explanation. gooooooooooooot it
Hope it helped! :)
Surely help. I hate probability, but love logic. hehehe...
Probability is nice, but there are a lot of terms to remember, and their definitions.