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Equation 2 if you would like to know why let me know.
plz tell me why
Okay, so for every other equation something is being raised to an expoenent, when something is being raised to an exponent this means that the line will be curved to a degree like this. |dw:1432948202275:dw|
And if its under a radical then thats a whole different story.
Medal or fan???
oh and i have one more question if you don't mind
Go aheda i'll help if i understand it
Which statement best explains whether y = 4x + 8 is a linear function or a nonlinear function? It is a linear function because the graph contains the points (8, 0), (12, 1), (16, 2), which are on a straight line. It is a nonlinear function because the graph contains the points (8, 0), (12, 1), (16, 2), which are not on a straight line. It is a linear function because the graph contains the points (0, 8), (1, 12), (2, 16), which are on a straight line. It is a nonlinear function because the graph contains the points (0, 8), (1, 12), (2, 16)
One moment let me graph this.
first off do you know how to graph it??
a little bit
Okay what is the slope in this case? and what is the y-intercept?
remember y=mx+b m being the slope and b, being the y-intercept.
No, here ill graph it so you can better understand it, the y-intercept is the b
i know it your y-intercept is 8
yes your y-intercept is 8
i don't see anything on the website
how do you even use this graphing calculator
plug in your equation.
the whole thing
remember slope is rise over run, so you would start at positive 8 to graph this then go down 4 left 1 or up 4 right 1
now what do i do after i have plugged in the equation
Okay i have your answer, but i wont give it to you yet.
So, tell me does your graph have any repeating x coordinates??
no, is correct and what does this mean?
is it a function or nonfunction?
that it is a linear function
Correct. now between your first choice and third choice which one do you think is corect? based of the information it tells you
Your third choice would be correct.
it is number three
Yep your right,
let me check if there is anything else that i need help with k
Alright ill be here
i am going to close this question and open a new one k